Answer: Un alambre de acero de 1.5 m se estira 2.0 mm con fuerza F. El diámetro del alambre de acero es 4.0 mm. El módulo de Young del acero es 2.0 x 1011 Nm-2. Determine la fuerza F aplicada sobre el alambre.
Step-by-step explanation:
Answer:
m∠E= 37°
m∠F=37°
Step-by-step explanation:
Total angle value: 180°
180-106=74
The lengths are the same, so we can determine that the angles E and F are the same. So we divide 74 by 2
74/2= 37
m∠E= 37°
m∠F=37°
Hope this helps! Have a nice day :)
Answer is 264
You just multiply at three numbers
34 and 34 I’m pretty sure
