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Harlamova29_29 [7]
2 years ago
6

I need help with problem 21

Mathematics
2 answers:
Paraphin [41]2 years ago
7 0
Aye bro it’s in the top left corner of the pic
leva [86]2 years ago
6 0

Answer:

X = 65

Step-by-step explanation:

The sum of the exterior angles of a polygon is 360°

Therefore, X + 111 + 50 + 36 + 98 = 360

Combine like terms:        X + 295 = 360

Subtract 295 from both sides:  X = 65

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What expression has a negative value?<br>7+3(-4)(2)<br>-2[12/(-3)]<br>(15-7)-(9/3)<br>-5[7+(-14)]-30
Soloha48 [4]

Answer:

7+3(-4)(2)= -17

Step-by-step explanation:

7+3(-4)(2)

(-4)*2=-8

∴ 7+3(-8)= 7-24

= -17

8 0
3 years ago
1.Graph f(x) = -1.5x +6<br> 2.Graph f(x) = -1/2x-5
nalin [4]

Ans(1):

Given equation is f(x)=-1.5x+6

we can plug any number like x=0 and x=2 to find the f(x) also called y-value

plug x=0

f(x)=-1.5x+6 =-1.5*0+6 =0+6 =6

Hence first point is (0,6)

plug x=2

f(x)=-1.5x+6 =-1.5*2+6 =-3+6 =3

Hence first point is (2,3)

now we can graph both points then join them to get final graph of f(x)=-1.5x+6

---------------------

Ans(2):

We can repeat exactly same process for f(x) = -1/2x-5.

So the final graph will look like attached picture:


5 0
3 years ago
A clothing store sells a customer 3 T-shirts and 4 pairs of shorts for $72.
ddd [48]

Answer:

C. t=$8, s=$12

Step-by-step explanation:

3($8)+4($12)=$72

4($8)+1($12)=$44

8 0
3 years ago
Find three consecutive even numbers whose sum is 1674.
Norma-Jean [14]

Answer:

556, 558, and 560

Step-by-step explanation:

1674/3 = 558 (An even number, yay)

So 558 + 558 + 558 = 1674

Subtract two from the first one and add two to the last (still equal)

556 + 558 + 560

adding them equals 1674 so the answer is

556, 558, and 560

7 0
3 years ago
1. What is the formula for Pythagorean Theorem
Debora [2.8K]

Answer:

The formula is a^2 + b^2 = c^2

Step-by-step explanation:

A and B are legs and C is the hypothunisis.

The theorem is used for triangles.

4^2  + 5^2 = c^2

16 + 25 = c^2

41 = c^2

sqr(41) = sqr(c)^2

c = 6.403124237

4 0
2 years ago
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