Answer:
I believe the answer would be
b.) valence electrons, all thw electrons that surround the nucleus of an atom
Explanation:
You're welcome
C the immigration rate is higher than the emigration rate
Answer:
10.6 moles of CO₂ are produced in this combustion
Explanation:
The combustion reaction is:
2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (g)
We assume the ethane as the limiting reactant because the excersise states that the O₂ is in excess.
We make a rule of three:
2 moles of ethane can produce 4 moles of CO₂
Therefore 5.30 moles of ethane will produce (5.3 . 4) /2 = 10.6 moles
Answer:
The molar mass is: 18.02 g/mol.
Explanation:
- Mass of two moles of Hydrogen atoms (H2) = 2x 1 g/mol = 2 g/mol.
- Mass of one mole of water (H2O) = 2 g/mol + 16 g/mol = 18 g/mol.
1 mole of Hydrogen= 1.01, so if we have 2 moles of it here, that would be 2.02.
1 mole of Oxygen (that's all we have here)= 16.00
Once you add the two together (2.02+16.00), you will get 18.02.
I hope this made sense! Have a great day!
Answer:
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Explanation:
Propane can be turned into hydrogen by the two-step reforming process.
In the first step, propane and water react to form carbon monoxide and hydrogen. The balanced chemical equation is:
C₃H₈(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g)
In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide. The balanced chemical equation is:
CO(g) + H₂O(g) ⇒ H₂(g) + CO₂(g)
In order to get the net chemical equation for the overall process, we have to multiply the second step by 3 and add it to the first step. Then, we cancel what is repeated.
C₃H₈(g) + 3 H₂O(g) + 3 CO(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g) + 3 H₂(g) + 3 CO₂(g)
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
