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arlik [135]
2 years ago
7

To prepare 1.00 L of 14g BaCl2, what Molarity would it be?​

Chemistry
1 answer:
nikklg [1K]2 years ago
6 0

Answer:

0.067 M  

Explanation:

Given data:

Volume of solution = 1.00 L

Mass of BaCl₂ = 14 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles first.

Number of moles = mass/ molar mass

Number of moles = 14 g/ 208.23 g/mol

Number of moles = 0.067 mol

Now we will calculate the molarity.

Molarity = 0.067 mol / 1.00 L

Molarity  = 0.067 M    ( mol/L=M)

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Answer:

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Explanation:

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Unknown:

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7 0
2 years ago
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pashok25 [27]

Answer:

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Explanation:

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                      In given question it is written that we are provided with one equivalent of HCl while, our compound contains two double bonds (diene) so in selected starting material the HCl will be added across (hydrohalogenation reaction) the substituted double bond because it will give a more stable carbocation (<u><em>tertiary carbocation</em></u>) during the reaction course. Hence, as shown in reaction scheme 4-chloro-4-methylcyclohex-1-ene will be the major product.

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