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arlik [135]
3 years ago
7

To prepare 1.00 L of 14g BaCl2, what Molarity would it be?​

Chemistry
1 answer:
nikklg [1K]3 years ago
6 0

Answer:

0.067 M  

Explanation:

Given data:

Volume of solution = 1.00 L

Mass of BaCl₂ = 14 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles first.

Number of moles = mass/ molar mass

Number of moles = 14 g/ 208.23 g/mol

Number of moles = 0.067 mol

Now we will calculate the molarity.

Molarity = 0.067 mol / 1.00 L

Molarity  = 0.067 M    ( mol/L=M)

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How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif
Katena32 [7]

<u>Answer:</u> The number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

<u>Explanation:</u>

Formula units are defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is 6.022\times 10^{23}

We are given:

Number of formula units of Sr(HCO_3)_2=4.55\times 10^{15}

As, 6.022\times 10^{23}  number of formula units are contained in 1 mole of a substance.

So, 4.55\times 10^{15} number of formula units will be contained in = \frac{1}{6.022\times 10^{23}}\times 4.55\times 10^{15}=7.5\times 10^{-9}mol of strontium bicarbonate.

Hence, the number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

5 0
3 years ago
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J.
timofeeve [1]

Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU +  w

q = 475 J  +  93 J

q = 568 J

Therefore, the magnitude of q for the process 568 J.

6 0
3 years ago
Sodium, atomic number 11, forms an ionic bond with an atom of an unknown element. What is one possible choice for the other elem
djyliett [7]
The Answer is A 
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3 0
3 years ago
Read 2 more answers
What is physical weathering? (1 point)
steposvetlana [31]

Answer:

well physical weathering is the process of a element or acts of water rock or other items that take its toll on items

Explanation:

so i would,WITH CONFIDENCE         C.

5 0
3 years ago
Read 2 more answers
PLEASE SOMEONE HELP ME WITH THIS!
Bad White [126]

Answer:

1) 1.202 L , 2) 1.291 dg , 3) 204.877  and 4) 1.04x10^{3\\}

Explanation:

You need to review about conversion factors and how to use them in the correct order. You can cancel the units and get the ones that you need if you use the appropriate conversion factors, remember is a number that you can use to multiply or divide.

For your exercise:

1) The conversion factor is: 1 L = 1000 mL

You will need to divide by 1000 mL to obtain liters L

1202.57120 mL x  \frac{1 L}{1000 mL} = 1.202 L

2) The conversion factor is: 1 g = 10 dg

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For the next exercises, you need to follow some rules:

1.  All numbers  that are different from Zero (non-zero digits) are significant figures.

2.The Zeros between non-zeros digits (Imbedded zeros) always are significant, 2007.

3. If you want to be specific and want some zeros to be significant you need to add a decimal point. For example 500. or 500.0

4. Leading zeros (to the left) are not significant.

5. Trailing zeros (zeros to the right) in a whole number without decimal point are not significant.

3) 843.062  - 638.1848  = 204.8772

Now if we round to 6 significant figures we get 204.877

4)123.0 x 8.43 = 1036.89

Now we round to 3 significant figures because 8.43 has the least significant figures.  

1.04x10^{3}

4 0
3 years ago
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