Short Answer:
Mutation is the changing of the structure of a gene
Step-by-step explanation:
Mutation is the changing of the structure of a gene, resulting in a variant form that may be transmitted to subsequent generations, caused by the alteration of single base units in DNA, or the deletion, insertion, or rearrangement of larger sections of genes or chromosomes.
Answer:
![y = 11(10) {}^{x}](https://tex.z-dn.net/?f=y%20%3D%2011%2810%29%20%7B%7D%5E%7Bx%7D%20)
Step-by-step explanation:
The standard form of exponential function is
![y = ab {}^{x}](https://tex.z-dn.net/?f=y%20%3D%20ab%20%7B%7D%5E%7Bx%7D%20)
Let plug in 0,11
![11 = ab {}^{0}](https://tex.z-dn.net/?f=11%20%3D%20ab%20%7B%7D%5E%7B0%7D%20)
anything to the 0 power equal 1 so b=1
![11 = a](https://tex.z-dn.net/?f=11%20%3D%20a)
Since we know 11 equal a here the equation rn
![y = 11(b) {}^{x}](https://tex.z-dn.net/?f=y%20%3D%2011%28b%29%20%7B%7D%5E%7Bx%7D%20%20)
Now let plug in 2,1110.
![1110 = 11(b) {}^{2}](https://tex.z-dn.net/?f=1110%20%3D%2011%28b%29%20%7B%7D%5E%7B2%7D%20)
Divide 11 by both
![y = 11(10) {}^{2}](https://tex.z-dn.net/?f=y%20%3D%2011%2810%29%20%7B%7D%5E%7B2%7D%20)
y=100 then take sqr root of 100 then b=10
Answer:
C.
Step-by-step explanation:
When we have an expression where the a number with an exponent is raised to another power, we simply apply one of the laws of exponents known as the power rule.
The rule says we just simply multiply the exponents together.
Thus, ![(a^m)^n = a^{m*n} = a^{mn}](https://tex.z-dn.net/?f=%20%28a%5Em%29%5En%20%3D%20a%5E%7Bm%2An%7D%20%3D%20a%5E%7Bmn%7D%20)
Therefore, the expression given, where we need to apply this rule is: ![(6^{10})^{-7} = 6^{10*-7} = 6^{-70}](https://tex.z-dn.net/?f=%20%20%286%5E%7B10%7D%29%5E%7B-7%7D%20%3D%206%5E%7B10%2A-7%7D%20%3D%206%5E%7B-70%7D%20%20)
The answer is C. ![(6^{10})^{-7}](https://tex.z-dn.net/?f=%20%286%5E%7B10%7D%29%5E%7B-7%7D%20)
The equation of the line segment through A and B is given as
-7x + 3y = -21.5
In standard form,
3y = 7x - 21.5
y = (7/3)x - 7.1667
Line AB has a slope of 7/3.
Let the equation of line segment PQ be
y = mx + b
Because line segments AB and PQ are perpendicular, therefore
(7/3)*m = -1
m = -3/7
The equation of PQ is
y = -(3/7)x + b
To find b, note that the line passes through the point (7,6). Therefore
6 = -(3/7)*7 + b
6 = -3 + b
b = 9
The equation of PQ is
y = - (3/7)x + 9
or
7y = -3x + 63
3x + 7y = 63
Answer: 3x + 7y = 63
It should be 6, radius is half of the circumference (6/3=2).