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professor190 [17]
3 years ago
14

What are the roles of the mucous select two options PLEASE HELP​

Chemistry
1 answer:
Oliga [24]3 years ago
8 0

Answer:

The answer is A and C

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If a chemical reaction such as photosynthesis begins with 6 atoms of carbon C , how many atoms of carbon C should be in the prod
pochemuha
B. 6 atoms of carbon C
I would think this is the answer, because one can't just delete or add atoms; otherwise, the equation would be unbalanced. This also abides with the Law of Conservation of Mass.

Plus, I also came to that conclusion because if we look at the net equation of photosynthesis:
6C O_{2} + 6H_{2}O ––> C_{6}H_{12}O_{6} + 6O_{2}
The number of Carbon atoms is 6 on both the reagent's side and the product's side.
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On a graph, which type of line shows a direct proportion? A. upwardly curved line B. downwardly curved line C. straight line D.j
siniylev [52]
A straight line shows a direct proportion because each x-value has one y-value, and there is a correlation between the two values, not just random placement. Hope this helps! :)
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What is aloneness???
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Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79
BARSIC [14]

Answer :  The mole fraction and partial pressure of CH_4,CO_2 and He gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of CH_4 = 1.79 mole

Moles of CO_2 = 1.20 mole

Moles of He = 3.71 mole

Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267

and,

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179

and,

\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }He=\frac{3.71}{1.79+1.20+3.71}=0.554

Thus, the mole fraction of CH_4,CO_2 and He gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 5.78 atm

X_i = mole fraction of gas

p_{CH_4}=X_{CH_4}\times p_T

p_{CH_4}=0.267\times 5.78atm=1.54atm

and,

p_{CO_2}=X_{CO_2}\times p_T

p_{CO_2}=0.179\times 5.78atm=1.03atm

and,

p_{He}=X_{He}\times p_T

p_{He}=0.554\times 5.78atm=3.20atm

Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

4 0
3 years ago
A hiker tries to prepare a hard-boiled egg on the high slopes of Mount Everest. The base camp is located 5,300 meters above sea
Igoryamba

Answer:

He will not have hard-boiled eggs for breakfast

Explanation:

The given parameters are;

The elevation at which the base camp of the hiker is located = 5,300 meters

The boiling point of water at the elevation of the base camp = 82°C

The temperature required to cook the raw egg = 100°C

Therefore, we have;

The temperature of the boiling water at the given elevation of the base camp 82°C < The temperature required to cook the raw egg 100°C

Therefore, the eggs will not be hard boiled.

7 0
3 years ago
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