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Lesechka [4]
3 years ago
15

Why is CN considered a weak base if its the conjugate base of a weak acid?

Chemistry
1 answer:
expeople1 [14]3 years ago
8 0
CN considered as a weak base even if its the conjugate base of a weak acid. When it is in aqueous solution, it accepts a hydrogen ion forming hydrogen cynide and an OH- ions which makes it a Bronsted -Lowry base. Also, it has a pKb of 4.79 which makes it basic in nature.
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Explain why hydrogen can only have 2 valence electrons around it when it bonds to other items. What is the maximum number of bon
lys-0071 [83]

Answer:

In first shell only 2 electrons are present in hydrogen only one electron is present in valence shell. To complete its duplet hydrogen can share lose or gain only one electron to form chemical bond.

Hydrogen can form only one bond.

Explanation:

7 0
3 years ago
How does air bubbles affect density of a solid object?
kirill [66]

it decreases the density of the object the air bubbles take up space. it increases the volume of the object slightly but the objects weight remains the same, hence the objects density decreases

6 0
3 years ago
Calculate the percent by volume of a solution that has 75 mL of solute dissolved in 375 mL of solution. Show your work and round
Mandarinka [93]

Answer:

The answer is 20 % V/V

Explanation:

We use this formula for calculate the %V/V:

%V/V= (ml solute/ml solution) x 100= (75ml/375 ml)x 100 = 20 % V/V

<em>The% V / V represents the amount of ml of solute dissolved in 100 ml of solution</em>

7 0
3 years ago
A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl
diamong [38]

Answer:

\large \boxed{\text{98 m$\cdot$s}^{-2}}

Explanation:

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v = \sqrt{2gh}

1. Velocity at time of impact

v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}

3. Acceleration

a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}

5 0
3 years ago
Please Help 8-9!!!!!!!
seropon [69]

The labeled diagram is given in the image attached.

As it can be seen from the image that freezing is when energy is removed from the system at 0 ⁰ while melting is when energy is added at 0⁰.

Also when energy is added at 100⁰C, it causes boiling while when it is removed at 100⁰C, it causes condensation.


Melting point of water is 0⁰C while boiling point is 100⁰C

3 0
3 years ago
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