Answer:18.02 grams
The average mass of one mole of H2O is 18.02 grams.
Explanation: we need to find the moles of water in 1 L of water or 1000mL of water. Taking the density of water to be 1g/mL, 1000mL of water= 1000g water.
Therefore, number of moles= given mass of water(1000)/molecular mass of water(18)
Moles =1000/18= 55.55
So total molecules in 55.55 moles= 55.55* 6.022*10^23 = 334.52*10^23 molecules
=3.34*10^25 molecules of water.
:)
The best statement
which describes a reaction in a state of equilibrium is letter D. <span>The rate of the forward
reaction equals the rate of the reverse reaction and the </span>concentrations of products and
reactants are constant.
>Chemical equilibrium<span> is defined as<span> the state in which both reactants and products are present
in </span></span>concentrations<span> which have no further tendency to change with time. This state results when the forward
reaction proceeds at the same rate as the </span>reverse
reaction<span>. The </span>reaction rates<span> of the forward and backward reactions are generally not zero,
but equal. Thus, there are no net changes in the concentrations of the reactant(s)
and product(s).</span>
<span> </span>
The relation between density, mass and volume is
1) to calculate = volume
given:
Density = 0.0915 g/ mL
mass = 17.7 grams
formula used:
Thus
Volume 
Answer: 193.44 mL
2) the mass of sample will be
Answer: 7 g
Answer:
metaphase
Explanation:
the cells chromosomes line themselves in the middle of the cell through a type of cellular tug of war.
