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3 years ago

PLEASE HURRY I WILL GIVE BRAINYEST

Chemistry

1 answer:

Mademuasel [1]3 years ago

8 0

Answer:

D. Between mountain ranges

Explanation:

Usually in between mountains is where the most grass is.

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Which molecule has a high specific heat? a) C2H6 b) C2H6O c) H2O

dem82 [27]

H2O is the correct answer :)

4 0

3 years ago

A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 30.0 g carbon and 40.0 g oxygen. Another sam

mote1985 [20]

Answer:

16.933g approximately 17.0 grams

Explanation:

From the simple promotions and given the same compound ascorbic acid (vitamin C)

In the laboratory synthesised ascorbic acid

Mass of carbon = 30.0g

Mas of Oxygen = 40.0g

That is the mass of Oxygen per unit mass of Carbon

Per gram of Carbon we have

(30.0g Carbon)÷30 combines with (40.0g of Oxygen)÷30

That is 4/3g of Oxygen per gram of Carbon

Hence the mass of Oxygen compound that combines with 12.7g of Carbonin natural occurring ascorbic acid (vitamin C) is = 4/3×12.7 = 16.933g approximately 17.0g

8 0

3 years ago

Three factors affecting gas pressure are the amount of gas, temperature, and __________.

Olenka [21]

It's A. volume
Pressure = $\frac{moles * const * temperature}{volume}$
with const depends on the chosen unit of volume
I think so...

8 0

3 years ago

Read 2 more answers

As refrigerant passes through the expansion valve, it cools down or heats up?

Yuri [45]

It cools down i am 100 percent sure it cools down

5 0

3 years ago

Read 2 more answers

A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t

andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

$\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)$

Where:

μ (l): is the chemical potential of 2-propanol in solution

μ° (l): is the chemical potential of pure 2-propanol

R: is the gas constant = 8.314 J K⁻¹ mol⁻¹

T: is the temperature = 82.3 °C = 355.3 K

x: is the mole fraction of 2-propanol = 0.41

$\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)$

$\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}$

$\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}$

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.

I hope it helps you!

8 0

4 years ago