According to given chemical reaction, one mole of carbon monoxide reacts with one mole of water results in the formation of one mole of calcium hydroxide.
Therefore, calcium monoxide and water reacts in one ratio one (1:1).
Now, in given chemical reaction, change in enthalpy is negative i.e. -65.2 kJ (less than zero).
The negative sign of change is enthalpy indicates that heat is released and the reaction in which heat is released is said to be exothermic reaction. Thus, the given reaction is exothermic i.e. heat is released.
Hence, 65.2 kJ of heat is released for every one mole of calcium monoxide which reacts is the correct statement for the given reaction.
The mole fraction of ethanol c2h5oh in an aqueous solution that is 46 percent ethanol by mass is 0.25
Mole fraction is the mole of one of the component of the solution divided by the total moles of the solution
Calculating the mole fraction of ethanol,we get
Percentage by weight of ethyl alcohol is 46% which implies in 100 g of this solution is 46 g while the mass of the water will be 54% of 100 g = 54g.
Finding the moles of water and the ethyl alcohol {molar mass of water(H₂O) = 18 and molar mass of ethyl alcohol(C₂H₆O = 46}
Moles = mass/molar mass
moles of ethanol = 46/46 = 1
moles of water = 54/18 = 3
ntotal=1+3=4
Mole fraction of ethanol is:
Mole of ethanol = 1/4
Total mole of solution
Hence, the mole fraction is 1/4 or 0.25
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This is done by reducing each number by a common factor for each formula.
C3H6O6- all can be divided by 3 -> CH3O3 (you don't have to put a 1 for C, only if your teacher requests it. It is generally understood if not written)
H2O2- all can be divided by 2 -> H1O1 (had to put the 1's bc of the unintended language)
C8H8S2- all can be divided by 2 -> C4H4S
P5O15- all can be divided by 5- PO3
*****it is important to note that <em>all </em>numbers in the molecular formula are divided by the same thing to reduce them. decimals are <em>never </em>used in empirical formulas, only whole numbers.*****
