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Anvisha [2.4K]
2 years ago
7

describe the journey that light takes from the sun to your eye when you are looking at fish in a pond

Physics
1 answer:
Tcecarenko [31]2 years ago
7 0

Rays of the light fast moves to the water and to the fish and then they are reflected

<u>Explanation:</u>

  • The movement of the light in the water and which to the fish taste of thence they are reflected by the upper surface of the water and reaches the eye, this results in The refraction in the lens of our eyes and it reaches the retina.
  • The retina consists of the photosensitive pigments that helps in the giving off the lights when the electrochemical neuronal activity reaches the brain of human beings

To know more,

this is the science that studies the physiographic units such as ..

.brainly.in/question/22161298

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Who’s going faster in the attached image?
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Explanation:

Polly's line is linear, while arts line is going up with constant velocity. There for art is going faster.

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Three balls of equal mass are fired simultaneously with equal speeds from the same height h above the ground. Ball 1 is fired st
pantera1 [17]

Answer:

d) v1 = v2 = v3

Explanation:

This can be answered using conservation of energy. We calculate the mechanical energy E=K+U (sum of kinetic and gravitational potential energies) at the original and final points, and impose they are equal.

At the original point we have, for the three balls:

E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh

At the final point we have, for the three balls:

E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}

Since we have E_i=E_f, and E_i is the same for all balls, then E_f is the same for all balls, which means that v_f, the final velocity, is the same for all balls.

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3 years ago
Technician A says that you can check a leaking head gasket using a chemical tester. Technician B says that you can find a leakin
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What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n
Yuri [45]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  wavelength is  \lambda  =  622 nm

Explanation:

  From the question we are told that

    The distance of the slit to the screen is  D  = 5 \ m

    The order of the fringe is m  =  6

     The distance between the slit is  d = 0.9 \ mm  =  0.9 *10^{-3} \ m

    The fringe distance is  Y =  1.9 \ cm  =  0.019 \ m

Generally the for a dark fringe the fringe distance is  mathematically represented as

        Y  = \frac{[2m  - 1 ] *  \lambda *  D  }{2d}

=>     \lambda  =  \frac{Y *  2 *  d }{[2*m  -  1] *  D}

substituting values

=>      \lambda  =  \frac{0.019 *  2 *  0.9*10^{-3} }{[2*6  -  1] *  5}

=>     \lambda  =  6.22 *10^{-7} \ m

       \lambda  =  622 nm

8 0
2 years ago
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