The amplitude did not change when the recurrence was expanded on the grounds that the long headstrong time of the heart forestalls adjustment. It is the most extreme removal or separation moved by a point on a vibrating body or wave measured from its balance position. It is equivalent to the one-a large portion of the length of the vibration way.
Answer:
Art
Explanation:
Polly's line is linear, while arts line is going up with constant velocity. There for art is going faster.
Answer:
d) v1 = v2 = v3
Explanation:
This can be answered using conservation of energy. We calculate the mechanical energy E=K+U (sum of kinetic and gravitational potential energies) at the original and final points, and impose they are equal.
At the original point we have, for the three balls:

At the final point we have, for the three balls:

Since we have
, and
is the same for all balls, then
is the same for all balls, which means that
, the final velocity, is the same for all balls.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The wavelength is
Explanation:
From the question we are told that
The distance of the slit to the screen is 
The order of the fringe is m = 6
The distance between the slit is
The fringe distance is 
Generally the for a dark fringe the fringe distance is mathematically represented as
![Y = \frac{[2m - 1 ] * \lambda * D }{2d}](https://tex.z-dn.net/?f=Y%20%20%3D%20%5Cfrac%7B%5B2m%20%20-%201%20%5D%20%2A%20%20%5Clambda%20%2A%20%20D%20%20%7D%7B2d%7D)
=> ![\lambda = \frac{Y * 2 * d }{[2*m - 1] * D}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7BY%20%2A%20%202%20%2A%20%20d%20%7D%7B%5B2%2Am%20%20-%20%201%5D%20%2A%20%20D%7D)
substituting values
=> ![\lambda = \frac{0.019 * 2 * 0.9*10^{-3} }{[2*6 - 1] * 5}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7B0.019%20%2A%20%202%20%2A%20%200.9%2A10%5E%7B-3%7D%20%7D%7B%5B2%2A6%20%20-%20%201%5D%20%2A%20%205%7D)
=> 
