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3 years ago

15

you and your friend each drive 70 miles you drive 60 miles/hour and your friend. drives 55 miles / hour how much sonner will you

finish your trip

1 answer:

oksian1 [2.3K]3 years ago

4 0

Answer:

Explanation: 60 mile/hour in 70 miles is 1 hour and 6 minutes and

55 miles/hour in 70 is 1 hour 21 minutes so you will get there 15 minutes earlier

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people will buy more of a good when its price falls and less when its price rises, according to the....

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People will buy more of a good when its price falls and less when its price rises, according to the law of demand.

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In a church choir loft, two parallel walls are 5.30 m apart. The singers stand against the north wall. The organist faces the so

morpeh [17]

The virtual image is as far behind the mirror as the choir is in front of the mirror. Thus, the image is 5.30 m behind the mirror. The image of the choir is 0.800 m+ 5.30 m= 6.10 m from the organist.

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h'/0.600 = 6.10/0.800

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2 years ago

Choose the pair of elements that will most likely have the least ionic character.

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I think the answer is c h and o

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2 years ago

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Ice skaters often end their performances with spin turns, where they spin very fast about their center of mass with their arms f

nekit [7.7K]

Answer:

Her angular speed (in rev/s) when her arms and one leg open outward is 1.4 rev/s

Explanation:

given information:

moment inertia of arm and leg when in, I₁ = 0.9 kgm²

moment inertia of arm and leg when extended, I₂ = 2.9 kgm²

angular speed when in, ω₁ = 4.5 rev/s

so, her angular speed (in rev/s) when her arms and one leg open outward is

L₁ = L₂

I₁ω₁ = I₂ω₂

ω₂ = I₁ω₁/I₂

= 0.9 x 4.5/2,9

= 1.4 rev/s

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3 years ago

A grinding wheel is in the form of a uniform solid disk of radius 7.00 cm and mass 2.00 kg. It starts from rest and accelerates

Veronika [31]

Answer:

Part a)

$t = 1.03 s$

Part b)

$N = 10.3 rev$

Explanation:

Mass of the disc is given as

m = 2.00 kg

radius of the disc is given as

r = 7 cm

so moment of inertia of the disc is given as

$I = \frac{1}{2}mr^2$

$I = \frac{1}{2}(2)(0.07)^2$

$I = 4.9 \times 10^{-3} kg m^2$

Now given that torque on the disc is

$\tau = 0.600 Nm$

so here the angular acceleration is given as

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{0.600}{4.9 \times 10^{-3}}$

$\alpha = 122.45 rad/s^2$

Part a)

if disc start from rest and then achieve final speed as 1200 rpm then

$f = 1200/60 = 20 rev/s$

so final speed is

$\omega = 2\pi(20) = 40\pi rad/s$

now the time taken to reach this speed is given as

$\alpha t = \omega$

$(122.45) t = 40\pi$

$t = 1.03 s$

Part b)

Number of revolution in the same time is given as

$N = \frac{\omega_o + \omega}{4\pi} t$

$N = \frac{40\pi + 0}{4\pi}(1.03) = 10.3 rev$

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3 years ago