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inn [45]
3 years ago
14

A student is testing the kinematic equations for uniformly accelerated motion by measuring the time it takes for light-weight pl

astic balls to fall to the floor from a height of 3 m in the lab. The student predicts the time to fall using g as 9.80 m/s2 but finds the measured time to be 35% greater. Which of the following is the most likely cause of the large percent error?
(A) The acceleration due to gravity is 70% greater than 9.80 m/s2 at this location.(B) The acceleration due to gravity is 70% less than 9.80 m/s2 at this location.(C) Air resistance increases the downward acceleration.(D) The acceleration of the plastic balls is not uniform.(E) The plastic balls are not truly spherical.
Physics
1 answer:
Soloha48 [4]3 years ago
3 0

Answer: Conclusion E

Explanation:

In this study we need to keep several things is mind.

First, the atracttion between two objects can be calculated using Newton's Universal Gravitation Equation:

F = G * \frac{M_{1} * M_{2}}{r^{2} }

Where the Force of attraction between two objects can be calculate by the product of the Gravitational Constant (G), their masses between the square of the distance. This same equation can be used to obtain the acceleration caused by gravity.

If we take in account this equation, we know that the Earth Mass is so big that any other will be attracted using the same force, no matter his size. Because of this, while the attraction between a Plastic Ball and a Rock should be different, the Earth's Mass makes irrelevant any weight like a little fluctuation.

Because of this, the Acceleration due Gravity should be constant between any object. A 70% bias is imposible. This made conclusions A, B and D Falses.

However the previous equation doesn't take in count the medium on which the two objects move. It is know that a object moving inside a fluid will experience friction which a force that oposses movemente and goes on the contrary direction, While the Plastic ball falls, the air around it will cause friction. This friction will always slow a falling object. Proving then, Conclusion C is false

In the case that a object falls, the air can provide resistant as proved before, however any irregularity on the surface of the ball can cause the ball to move and making the fall not truly straight, this can increase the time travel of the ball and slowing the ball fall. For this Conclusion E is the most likely to cause the error

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A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The
Damm [24]

Answer:

ugmd = 1/2 kx²

d = (1/2 kx²) / (ugm)

= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)

= 7.4 m

ugmd = 1/2 mv²

v = √2ugd

= √(2(0.23)(9.81 m/s²)(7.4 m)

= 5.8 m/s

Explanation:

3 0
3 years ago
For a star with a parallax angle of 1/2 of an at arcsecond, what will be its distance in parsec?
avanturin [10]

(1 parsec) is the distance at which an object has a parallax of 1 arcsecond. The distance is about 3.26 light years.

Another way to understand it is:  The distance from which the Earth's orbit appears 1 arcsecond across.

For a parallax angle of 1/2 arcsecond, the distance is <em>2 parsecs </em>(about 6.52 light years).

1 arcsecond is 1/3600 of a degree, 0.00028 degree.  

8 0
3 years ago
Which of the following statements below is correct?
Mamont248 [21]
C. is correct. when you make a pizza, you see the the meat or pepperoni or cheese heating up and sometimes melted. (thats physical). on the inside the crust in heated and the toppings are cooked (chemical)
5 0
3 years ago
Review:
Tresset [83]

Answer:

1. 1. A quantity is completely described by magnitude alone. A quantity Is completely described by a magnitude with a direction.

[a]. scalar, vector

b. vector, scalar

2.2. Speed is a velocity is a quantity and quantity.

a. scalar, vector

[b]. vector, scalar

3 0
2 years ago
The nucleus of a hydrogen atom is a single proton, which has a radius of about 1.2 × 10-15 m. The single electron in a hydrogen
Nutka1998 [239]

Answer: 0.86 × 10^14

Explanation:

Given the following :

Radius of proton = 1.2 × 10-15 m

Radius of hydrogen atom = 5.3 × 10-11 m

Density of proton could be calculated thus:

Mass of proton = 1.67 × 10^-27 kg

Using the formula :

(4/3) × pi × r^3

(4/3) × 3.142 × (1.2 × 10^-15)^3 = 7.24 × 10^-45

Density = mass / volume

Density = (1.67 × 10^-27) / ( 7.24 × 10^-45)

= 0.2306 × 10^18

Density of hydrogen atom:

Mass of hydrogen atom= 1.67 × 10^-27 kg

Using the formula :

(4/3) × pi × r^3

(4/3) × 3.142 × (5.3 × 10^-11)^3 = 6.24 × 10^-31

Density = mass / volume

Density = (1.67 × 10^-27) / ( 6.24 × 10^-31)

= 0.2676 × 10^4

Ratio is thus:

Density of proton / density of hydrogen atom

0.2306 × 10^18 / 0.2676 × 10^4 = 0.8617 × 10^14

6 0
3 years ago
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