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3 years ago

How much is the moon in the first quarter actually lit

Physics

2 answers:

grandymaker [24]3 years ago

8 0

Half of the moon is illuminated.

slamgirl [31]3 years ago

7 0

There's always 50% (half) of the moon lit by the sun. The thing that changes is how much of the lit part we can see.

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Unit Test

irina [24]

Neutrons

Explanation:

Atoms of the same elements are called isotopes. They differ from other atoms in the number of neutrons they posses. They share the same chemical properties but only differ with regards to their mass number.

Isotopy is a phenomenon whereby an atom of an element exist in more than one form but they have the same atomic number.
Atoms of such element only differ in the number of neutrons they contain.
Since the mass number of an atom is the sum of protons and neutrons, they differ in this number too
Isotopes have the same chemical properties.

learn more:

Isotopes brainly.com/question/10862182

#learnwithBrainly

6 0

3 years ago

A piston absorbs 25 J of heat from its surroundings while expanding from

Ivahew [28]

The work done is -30 J
The heat is 25 J

We know that the work done by a gas could be positive or negative same as the heat. If the work done is positive then work is done on the system.

The work done is obtained from;

W = PΔV

W = 1.0 x 105 Pa(0.0006 m³ - 0.0003 m³)

W = 30 J

Given that the gas absorbs heat from the surroundings and the gas is expanding.

The work done is -30 J
The heat is 25 J

Learn more about work done on a gas:brainly.com/question/12539457

#SPJ1

6 0

1 year ago

In a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallw

RSB [31]

Answer:

The coefficient of kinetic is

$u_{k}=0.59$

Explanation:

The forces in the axis 'x' and 'y' using law of Newton to find coefficient of kinetic friction

ΣF=m*a

ΣFy=W-N=0

ΣFy=Fn-Fu=m*a

$F_{u} =u_{k} *N\\F_{N}=25N\\N=W\\N=3.5kg*9.8\frac{m}{s^{2} }=34.3N$

$F_{N}-F_{u}=m*a\\F_{N}-u_{k}*N=m*a\\u_{k}*N=F_{N}-m*a\\u_{k}=\frac{F_{N}-m*a}{N}$

Now to find the coefficient can find the acceleration using equation of uniform motion accelerated

$v_{f} ^{2}=v_{o}^{2}+2*a(x_{f}-x_{o})\\x_{o}=0\\v_{o}=0\\v_{f} ^{2}=2*a*x_{f}\\a=\frac{v_{f} ^{2}}{2*a*x_{f}}\\ a=\frac{(1.53\frac{m}{s} )^{2}}{2*0.91m}\\a= 1.28 \frac{m}{s^{2} }$

So replacing the acceleration can fin the coefficient:

$u_{k}=\frac{F_{N}-m*a }{N}\\u_{k}=\frac{25N-(3.5kg*1.28\frac{m}{s^{2}} }{34.3N} \\u_{k}=0.59$

5 0

3 years ago

A 400.0 kg storage box is held 10 m above ground by a forklift. What is its gravitational potential energy? (PE = mgh)

castortr0y [4]

Answer: D.) 39,200 J

Via the equation of potential energy PE = mgh where m is mass, g is the average gravity on earth and h is the height. In this case m = 400 kg, g = 9.8, h = 10 m thus:

$P.E.=(400kg)(9.8\frac{m}{s^2} )(10m)=39,200 J$

P.E.= 39,200 Joules

7 0

3 years ago

Read 2 more answers

D the element in blue square has a full outer shell, due to it’s location on the periodic table, so it will not react with other

Juliette [100K]

The correct response that will be used to describe this particular element would be the third option, since all of the other options are incorrect and apply to different elements in their groups. The element is a metal and will react with a non metal.

5 0

3 years ago