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lesantik [10]
3 years ago
10

When Einstein's theory of gravity (general relativity) gained acceptance, it demonstrated that Newton's theory had been

Physics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

incomplete

Explanation:

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He is best known for publishing an almanac based on my astronomical calculations. Who is it?
slega [8]

Benjamin Banneker did this in 1792. Hope this helps

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4 years ago
An elevator has the mass of 3 tons of power needed to raise the elevator 50m in 15 s?PLEASE HELP PLEASE IM SCARED
madreJ [45]

Answer:

Time=15,Mass=3,Acceleration due to gravity=10,Height=50,Power=?.

Power=mgh/t.....which is 3×10×50=1500/15=100Watts.

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3 years ago
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What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4
mrs_skeptik [129]

Answer:

x = 2\sqrt 2

Explanation:

Given

Hypotenuse = 4

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

x^2 + x^2 = 4^2 --- i.e. the other legs are equal

So, we have:

2x^2 = 16

Divide both sides by 2

x^2=8

Take square roots of both sides

x = \sqrt 8

Simplify

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5 0
3 years ago
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Just wondering, what do you guys think the 5th dimension is? I've always believed it to be light.
zepelin [54]

Answer: In the 5th dimension, they who claim to know, say that there is only one time, including the past and the future.

8 0
3 years ago
Calculate the potential energy of a 1200 kg boulder on a cliff 45 m above the ground. ​
Softa [21]

Explanation:

Given mass of the object is 1200kg and it's placed at a height of 45m above the ground. As we know that potential energy is ,

\longrightarrow PE = mgh

where,

  • m is the mass of the body .
  • g is acceleration due to gravity.
  • h is the height above the ground .

Substituting the respective values ,

\longrightarrow P.E. = 1200kg * 10m/s^2* 45m

Multiply ,

\longrightarrow P.E. = 540000J

<u>Hence</u><u> the</u><u> </u><u>potential</u><u> energy</u><u> is</u><u> </u><u>5</u><u>4</u><u>0</u><u>0</u><u>0</u><u>0</u><u>J</u><u> </u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>

4 0
3 years ago
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