Question

If a driver brings a car traveling at 22m/s to a full stop in 2.0 s with an acceleration of -8 m/s2 then how far did the car travel while braking?

Answer 1

Answer:

v=u + at

0= 22 + a*2

a = -22/2 = -11 m/s^2

The car's acceleration is -11 m/s^2

V^2 = u^2 + 2as

022^2 + 2*(-11)s

s = 22^2/22 = 22m

The car will travel 22 m before stopping.

Explanation:

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