Answer:
c) 2 blocks
Explanation:
Her displacement is the difference between her starting point and her ending point.
Let's say she starts at the origin, (0, 0).
First, she goes 13 blocks east: (13, 0)
Next, she goes 4 blocks north: (13, 4)
Then she goes 8 blocks west: (5, 4)
Then she goes 6 blocks south: (5, -2)
Finally, she goes 5 blocks west: (0, -2)
The magnitude of her displacement is the distance between her initial and final positions: 2 blocks.
Answer:
d
Explanation:
it has high pressure of speed
Answer:
+14.0 m/s
Explanation:
we have mV + Mv = mU + Mu we solve for U = (mV + Mv - Mu)/m = (328*19.1 + 790*13 - 790*15.1)/328 = 14. Answer
Answer:
The orbital speed of the satellite around the earth in other to remain in perfect circular orbit in given as:
v = sqrt[(Ge*M)/R],
where Ge is the gravitational constant (Ge = 6.673 x 10^-11N/m2/kg2), M is the mass of the earth(m = 5.98 x 10^24kg), and R is the radius of the earth (R = 6.47 x 10^6m)
v = SQRT [ (6.673 x 10^-11 N m2/kg2) • (5.98 x 10^24 kg) / (6.47 x 10^6 m) ]
v = 7.85 x 10^3 m/s
Explanation:
For a satelite in a low altitude orbit around the Earth, the gravitational force is the only force acting of the said satellite keeping it is a circular orbit. To keep this satellite in perfect circular orbit, it must be moving in at a certain speed, which is dependent on the earth mass and radius. This speed can be evaluated from the expression of centripetal force(F = mv2/r). The centripetal force Fc on the satellite is equal to the gravitational force on the satellite from the earth(Fe). That is, (Ge*M*m)/R2 = (m*v2)/R, where M is mass of the earth, and m is the mass of the satellite. making v the subject of the formula, the equation become v = sqrt[(Ge*M)/R].
Answer:
(a) v = 15m/a
(b) No they won't feast because the rock can only rise to a height of 11.5m which is less than 15m.
Explanation:
Please see the attachment below for film solution.
