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harina [27]
3 years ago
12

If you could see the electric field coming off a proton you would notice that electric field lines are what?

Physics
1 answer:
Readme [11.4K]3 years ago
3 0
The electric field generated by a proton is a radial field, so we would see the field lines going radially from the proton toward every direction. I've attached a picture representing the electric field generated by a positive charge, such as a proton, and we can see the field lines going radially from the charge toward every direction. 

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A 300 N force acts on a 25 kg object. The acceleration of the object is?
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Acceleration is F/M so the answer would be 12m/s^2
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Why freezer is made in the upper part of refrigrator
svp [43]
<h2>Question</h2>

why freezer is made in the upper part of refrigrator

<h2>✒ Answer</h2>

the cold air produced from it is denser than the warmer air in the bottom

<h3>Explaination</h3>

Freezer is normally provided at the top of the refrigerator, because density of the cold air is high compared to the hot air. In a refrigerator the air contacts with the cooling coil and gets cooling.Because of the high density the cold air gets down and the warm air/hot air moves upward and gets cooling from the cooling coil/evaporator coil. This process is repeated. If the Freezer is provided at the bottom place of the refrigerator, the cold air can't to move full area of the refrigerator. So the freezer is normally provided at the top at the refrigerator

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2 years ago
Why do heavier objects fall at the same speed as lighter ones?
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Speed of any freely falling object is always same. Provided, both are left to fall from the same height. If you perform this experiment in a perfect vacuum or near vacuum laboratory, both of them will reach ground with same velocity this is because there is no resistance to their motion. This is always true no matter where you go and perform this experiment. 
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A violin string E vibrates faster then another violin string G when bowed. Which string produced a sound with higher frequency?​
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Violin string E

!!!!!!!!!!!!!!

5 0
2 years ago
A ray of light in air is incident on the mid-point of a heavy flint glass prism surface at an angle of 20º with the normal. for
Nata [24]
Assuming that you have a triangular prism, the ray of light will undergo refraction twice. The first time is the transition from air to flint glass on the entry face, and the second time is the transition from the flint glass to air from the exit face. With the available data, there are two possible solution since saying "20Âş from the normal" isn't enough information. Depending upon which side of the normal that 20 degrees is, the interior triangle will have the angles of 35, 90-r, and 55+r, or 35, 90+r, 55-r degrees where r is the angle from the normal after the 1st refraction. I will provide both possible solutions and you'll need to actually select the correct one based upon the actual geometry which I don't know because you didn't provide the figure or diagram that you were provided with.    

The equation for refraction is:  

(sin a1)/(sin a2) = n1/n2  

where  

a1,a2 = angles from the normal to the surface.  

n1,n2 = index of refraction for the transmission mediums.    

For this problem, we've been given an a1 of 20Âş and an n1 of 1.60. For n2, we will use air which at STP has an index of refraction of 1.00029. So  

(sin a1)/(sin a2) = n1/n2  

(sin 20)/(sin a2) = 1.00029/1.60  

0.342020143/(sin a2) = 0.62518125  

0.342020143 = 0.62518125(sin a2)  

0.547073578 = sin a2  

asin(0.547073578) = a2  

33.16647891 = a2    

So the angle from the normal INSIDE the prism is 33.2Âş. The resulting angle from the surface of the entry face will be either 90-33.2 or 90+33.2 depending upon the geometry. So the 2 possible triangles will be either 35Âş, 56.8Âş, 88.2Âş or 35Âş, 123.2Âş, 21.8Âş. with a resulting angle from the normal of either 1.8Âş or 68.2Âş. I can't tell you which one is correct since you didn't tell me which side of the normal the incoming ray came from. So let's calculate both possible exits.    

1.8Âş  

(sin a1)/(sin a2) = n1/n2  

(sin 1.8)/(sin a2) = 1.6/1.00029  

0.031410759/(sin a2) = 1.599536135  

0.031410759= 1.599536135(sin a2)  

0.019637418= sin(a2)  

asin(0.019637418) = a2  

1.125213477 = a2    

68.2Âş  

(sin a1)/(sin a2) = n1/n2  

(sin 68.2)/(sin a2) = 1.6/1.00029  

0.928485827/(sin a2) = 1.599536135  

0.928485827 = 1.599536135(sin a2)  

0.58047193 = sin a2 

 asin(0.58047193) = a2 

 35.48374252 = a2   

 So if the interior triangle is acute, the answer is 1.13Âş and if the interior triangle is obtuse, the answer is 35.48Âş
5 0
3 years ago
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