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2 years ago

Can someone pls tell me where a wet piece of a roll can mold the fastest?

Chemistry

2 answers:

Zigmanuir [339]2 years ago

5 0

I suggest for you to leave it in a moist spot! Also if any sort of light is there; it can probably help as well!

mojhsa [17]2 years ago

3 0

The moistest / warmest spot

You might be interested in

Which term describes matter that is a substance made of diffrent kinds of atoms bonded together

Alex777 [14]

Compounds are substances made of at least 2 different elements. Molecules have at least 2 atoms, doesn't have to be different elements. Compounds and molecules both work.

8 0

3 years ago

1) a solution with a hyrdrogen ion concentration of 1x10^-4 moles/liter would have a PH of what?

lana66690 [7]

Answer:

pH = -log(concentration of hydro.gen ion)

1. When con. of H ion is 1*10-4 mol/L

pH = -log(1*10-4) = -(-4) = 4

2. A solution with a pH of 1*10-12mol/L

pH = -log (1*10-12) = -(-12) = 12

The pH is 12 and the solution is basic or alkaline

3.A solution with a pH of 6 has the concentration of

pH = -log (H+)

(H+) = arc log -pH

(H+) = 1*10-6

Explanation:

7 0

3 years ago

What term describes isotopes with an unbalanced number of neutrons?

MAVERICK [17]

It might be radioactive

5 0

3 years ago

Since acids have 1 more proton (H+ - ions) than base, and the acid gives it away, doesn't that mean that they switch roles? Acid

andreev551 [17]

Answer:

In an acid-base equilibrium, acid becomes a conjugate base and base becomes a conjugate acid.

Explanation:

Let's remember the Bronsted-Lowry theory to answer this specific question. According to the theory, acid is a proton donor, while a base is a proton acceptor.

Consider an acid in a form HA (aq) and base in a form of B (aq). Since acid is a proton donor, it will donate its hydrogen ion to the base, B. The resultant products would be $A^{-}$ (aq) and $BH^{+}$ (aq).

Remember that an acid-base reaction is an equilibrium reaction. This means we may also look at this proton transfer reaction from the product side towards the reactants. Summarizing what has been said, we may write the equilibrium as:

$HA (aq) + B (aq)$ ⇄ $BH^{+} (aq) + A^{-} (aq)$

Now acid, HA, donates a proton to become a conjugate base. The conjugate base, if we look from the reverse equation side, is actually a base, since it can accept a proton to become HA. Similarly, B accepts a proton to become a conjugate acid. Looking from the reverse reaction, it can now donate a proton, so in reality we can consider it a base.

To summarize, your logic is correct.

6 0

3 years ago

Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g), Kgoal=? by making use of the followi

marta [7]

Answer : The value of $K_{goal}$ for the final reaction is, $1.238\times 10^{-7}$

Explanation :

The following equilibrium reactions are :

(1) $2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2$ $K_1=5.40\times 10^{-16}$

(2) $2H_2(g)+O_2(g)\rightleftharpoons 2H_2O(l)$ $K_2=1.06\times 10^{10}$

(3) $CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g)$ $K_3=2.68\times 10^{-9}$

The final equilibrium reaction is :

$CO_2(g)\rightleftharpoons C(s)+O_2(g)$ $K_{goal}=?$

Now we have to calculate the value of $K_{goal}$ for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

$K_{goal}=\sqrt{K_1\times K_2\times K_3}$

Now put all the given values in this expression, we get :

$K_{goal}=\sqrt{(5.40\times 10^{-16})\times (1.06\times 10^{10})\times (2.68\times 10^{-9})}$

$K_{goal}=1.238\times 10^{-7}$

Therefore, the value of $K_{goal}$ for the final reaction is, $1.238\times 10^{-7}$

3 0

3 years ago