Three electromagnetic waves travel through a certain point P along an x axis. They are polarized parallel to a y axis, with the
following variations in their amplitudes.
Find their resultant at P.E1 = (4 × 10^-5 V/m) sin[(5 × 10^14 rad/s)t]E2 = (6 × 10^-6 V/m) sin[(5 × 10^14 rad/s)t + 45°]E3 = (6 × 10^-6 V/m) sin[(5 × 10^14 rad/s)t - 45°]
Find their resultant at P.E1 = (4 × 10^-5 V/m) sin[(5 × 10^14 rad/s)t]E2 = (6 × 10^-6 V/m) sin[(5 × 10^14 rad/s)t + 45°]E3 = (6 × 10^-6 V/m) sin[(5 × 10^14 rad/s)t - 45°]
1 answer:
Answer:
Explanation:
Frequency of each electromagnetic wave is same thus we can interfere them along X axis in Phase diagram.
In phase diagram indicate each wave as vector with amplitude as length and phase difference as angle. (shown in attachment)
Now take component of E2 and E3 amplitude along X direction.
Net amplitude of all E in X direction = + cos(45)[
+
]
⇒
Final resultant have no change in frequency
So , resultant is
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These 255.75 Hz and 256.25 Hz sounds can be thought of as a sum of two waves with frequencies.
Answer: Option A
<u>Explanation:</u>
To solve this, it is necessary to take into account the concepts related to frequency and period, and how they are related to each other.
Let frequency of beat = f
The relationship that defines both agreements is given by the equation,
Then the frequency for the previous period given (2sec) is
The beat frequency of two frequencies is equal to the difference between the two frequencies, then
Hence, Option A is correct.
Similarly we can check like these for other options too as below,
For option B, .
For Option C,
For Option D,
For Option E,
Therefore, the sum of the frequencies in the sound wave would be 256.25Hz and 255.75Hz.