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-BARSIC- [3]
4 years ago
10

Three electromagnetic waves travel through a certain point P along an x axis. They are polarized parallel to a y axis, with the

following variations in their amplitudes.
Find their resultant at P.E1 = (4 × 10^-5 V/m) sin[(5 × 10^14 rad/s)t]E2 = (6 × 10^-6 V/m) sin[(5 × 10^14 rad/s)t + 45°]E3 = (6 × 10^-6 V/m) sin[(5 × 10^14 rad/s)t - 45°]

Physics
1 answer:
chubhunter [2.5K]4 years ago
6 0

Answer:

4.846*10^{-5} sin(5*10^{14}t )

Explanation:

Frequency of each electromagnetic wave is same thus we can interfere them along X axis in Phase diagram.

In phase diagram indicate each wave as vector with amplitude as length and phase difference as angle. (shown in attachment)

Now take component of E2 and E3 amplitude along X direction.

Net amplitude of all E in X direction = 4*10^{-5} + cos(45)[ 6*10^{-6} +  6*10^{-6} ]

⇒  4.846*10^{-5}

Final resultant have no change in frequency

So , resultant is 4.846*10^{-5} sin(5*10^{14}t )

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Betty weighs 420 n and she is sitting on a playground swing seat that hangs 0.40 m above the ground. tom pulls the swing back an
Svet_ta [14]
Weight = mass * gravity
420 = mass * 9.8
mass of Betty = 42.857 kg

Difference in height = 1 - 0.45 = 0.55 meters

Total energy = Kinetic energy + potential energy

At the highest point, the kinetic energy is zero while the potential energy is maximum, therefore, we can get the total energy as follows:
Total energy = 0 + mgh
Total energy = 42.857*9.8*0.55 = 231 Joules

At the lowest point, the potential energy is zero while the kinetic energy is maximum. Therefore:
Total energy = 0.5 * m * (v)^2 + 0
231 = 0.5 * (42.857) * (velocity)^2
(velocity)^2 = 10.78
velocity = 3.28 meters/sec
8 0
4 years ago
Consider a river flowing toward a lake at an average velocity of 3 m/s at a rate of 590 m3/s at a location 90 m above the lake s
Norma-Jean [14]

Explanation:

Given data

Velocity v=3 m/s

Water volume flow rate V=590 m³/s

Water elevation z=90 m

Water density p=1000 kg/m³

First we need to determine the energy per unit mass

So

e_{mech:}=e_{kine:}+e_{potent:}\\e_{mech:}=e_{potent:}\\e_{mech:}=gz\\e_{mech:}=9.81m/s*90m\\e_{mech:}=882.9J/kg\\or\\e_{mech:}=0.8829kJ/kg

Now the power generation potential is:

\\W=m.e_{mech:}\\where\\m=pV_{volume}\\So\\W=pV_{volume}e_{mech:}\\W=1000kg/m^{3}*590m^{3}/s*882.9j/kg\\W=5.21*10^{8}W\\or\\W=520911kW\\or\\W=521MW

8 0
3 years ago
A pressure cooker is a pot whose lid can be tightly sealed to prevent gas from entering or escaping. Even without knowing how bi
k0ka [10]

Answer:

a) F₁₂₀ = 1.34 pa A  , b)  F₂₀ = 0.746 pa A

Explanation:

Part. A .    The definition of pressure is

         P = F / A

As the air can approach an ideal gas we can use the ideal gas equation

        P V = n R T

Let's write this equation for two temperatures

       P₁ V = n R T₁

       P₂2 V = n R T₂

       P₁ / P₂ = T₁ / T₂

point 1 has a pressure of P₁ = pa and a temperature of (20 + 273) K, point 2 is at (120 + 273) K, we calculate the pressure P₂

       P₂ = P₁ T₂ / T₁

       P₂ = pa 393/293

       P₂ = 1.34 pa

We calculate the strength

       P₂ = F₁₂₀ / A

       F₁₂₀ = 1.34 pa A

Part B

In this case the data is

Point 1 has a temperature of 393K and an atmospheric pressure (P₁ = pa), point 2 has a temperature of 293K, let's calculate its pressure

        P₁ / P₂ = T₁ / T₂

       P₂ = P₁ T₂ / T₁

       P₂ = pa 293/393

       P₂ = 0.746 pa

Let's calculate the force (F20), from this point

      F₂₀ / A = 0.746 pa

     F₂₀ = 0.746 pa A

6 0
3 years ago
Para proteger un computador de sobrecargas eléctricas, Juan coloca un filamento delgado de cobre llamado fusible en su circuito,
Verdich [7]

Answer:

Los fusibles están diseñados de tal forma que estos se "rompen" o se funden, cuando la demanda eléctrica supera un dado valor (cuando demasiada electricidad pasa a través de el).

Una vez el filamento se rompe, la corriente ya no puede circular por el (podes pensar en esta situación como un cable roto, la electricidad no puede circular por este cable)

Entonces, al romperse el filamento, en caso de una sobrecarga eléctrica, el flujo de electricidad se corta, y de esta forma se protege al computador de posibles sobrecargas.

4 0
3 years ago
A 2150 kg satellite used in a cellular telephone network is in a circular orbit at a height of 780 km above the surface of the e
Tom [10]

Answer:

a)F=16741.9N

b)\frac{F}{W}=0.795

Explanation:

The gravitational force on the satellite is calculated with Newton's Gravitation Law:

F=\frac{GMm}{r^2}

Where M=5.97\times10^{24}kg is Earth's mass, m=2150kg is the satellite mass, r=R+h is the distance between their centers, where h=780000m is the height of the satellite (from Earth's surface) and R=6371000m is Earth's radius, and G=6.67\times10^{-11}Nm^2/kg^2 is the gravitational constant.

a) With these values we then have:

F=\frac{GMm}{r^2}=\frac{(6.67\times10^{-11}Nm^2/kg^2)(5.97\times10^{24}kg)(2150kg)}{(6371000m+780000m)^2}=16741.9N

b) And the fraction this force is of the satellite’s weight <em>W=mg</em> is:

\frac{F}{W}=\frac{GMm}{mgr^2}=\frac{GM}{gr^2}=\frac{(6.67\times10^{-11}Nm^2/kg^2)(5.97\times10^{24}kg)}{(9.8m/s^2)(6371000m+780000m)^2}=0.795

5 0
4 years ago
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