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2 years ago

How many molecules are in 34.7 grams of water?

Chemistry

1 answer:

Anika [276]2 years ago

8 0

Answer:

This part require data such as Avogadro's number and the molar mass of water. But first, let's find the mass of water in the specified volume by making use of the density formula:

Density = mass/volume

1 g/mL = Mass/70 mL

Mass = 70 g

Each water contains 18 grams per mole, and each mole contains 6.022×10²³ molecules of water. Thus,

70 g * 1mole/18 g * 6.022×10²³ molecules/mole = 2.342×10²⁴ molecules of water

Explanation:

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Molecule of water contains hydrogen and oxygen in a 1:8 ratio by mass. This is a statement of __________.A) the law of multiple

fgiga [73]

Answer:

The correct answer is B.

Explanation:

The molecule of water has 2 atoms of hydrogen and 1 atom of oxygen.

The ratio of masses are given as:

$2\times 1 g/mol: 1\times 16 g/mol= 1 : 8$

This illustrates the law of definite proportions which is also known as law of constant compositions .

The law states that 'the elements combining to form compound always combine in a fixed ratio by their mass.'

Whereas :

Law of multiple proportion states that when two elements combine with each other to form more than one compounds , the mass of one element with respect to the fixed mass of another element are in ratio of small whole numbers.

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

In a balanced chemical reaction ,total mass on the reactant side must be equal to the total mass on the product side.

Law of conservation of energy states that energy can neither be created nor be destroyed but it can only be transformed from one form to another form.

7 0

3 years ago

Which of the following aqueous solutions will have the lowest vapor pressure at 25°C?

Vladimir79 [104]

C. 1.0 M Al2O3 would be the best answer

8 0

3 years ago

Read 2 more answers

Bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter

Alisiya [41]

Answer:Hence, the bond length in HCl is 125 pm.

Explanation:

Bond length : It is an average distance between the nuclei of two bonded atoms in a molecule.

Also given that bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter-nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Beyond this if atoms come closer to each other then their will be repulsion between them.

So, the bond length between the Hydrogen and Chlorine atom in HCl molecule is :

$Bond length=radius _{hydrogen}+radius_{chlorine}=25pm+100pm=125pm$

Hence, the bond length in HCl is 125 pm.

5 0

3 years ago

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How many moles of aluminum oxide (Al2O3) can be produced from 12.8 moles of oxygen gas (02)

zhannawk [14.2K]

Answer:

Theoretical Yield

Percent yield

Example stoichiometry problem

How much oxygen can be prepared from 12.25 g KClO3 . (Use molar mass KClO3 = 122.5 g.)

Most stoichiometry problems can be solved using the following steps.

Step 1.

Write and balance the equation for the decomposition of KClO3 with heat (∆). 2KClO3 + ∆ → 2KCl + 3O2

Step 2.

Convert what you have (in this case g KClO3) to moles.

# moles = grams/molar mass = 12.25 g /122.5 = 0.100 mole KClO3.

Step 3.

Using the coefficients in the balanced equation, convert moles of what you have (moles KClO3) to moles of what you want (in this case moles oxygen).

0.100 mol KClO3 x (3 moles O2/2 moles KClO3) = 0.100 x (3/2) = 0.150 mole O2.

Step 4.

Convert moles from step 3 to grams.

moles x molar mass = grams

0.150 mole O2 x (32.0 g O2/mole O2) = 4.80 g O2 produced from 12.25 g KClO3. This is the theoretical yield. If the ACTUAL yield is 4.20 grams, calculate percent yield. Percent yield = (actual yield/theoretical yield) x 100 = (4.20/4.80) x 100 = 87.5% yield

NOTE: In step 1, moles can be obtained other ways; in step 4 moles can be converted to other units.

a. For solutions, M x L = moles (or mL x M = millimoles).

b. For gases, L/22.4 = moles

4 0

3 years ago

The density of gold is 19.3 g /cm cubed The density of iron pyrite is 5.0 g /cm cubed. Is a nugget of iron pyrite and a nugget o

telo118 [61]

If you clear volume in the density equation:

$\rho = \frac{m}{V}\ \to\ V = \frac{m}{\rho}$

The greater the density the lower the volume. This means, the volume of gold nugget will be smaller than the volume of iron pyrite nugget.

$V_{gold} = \frac{m}{\rho} = \frac{50\ g}{19.3\ g/cm^3} = \bf 2.59\ cm^3$

$V_{iron} = \frac{m}{\rho} = \frac{50\ g}{5.0\ g/cm^3} = \bf 10\ cm^3$

6 0

3 years ago