All categories

2 years ago

How many molecules are in 34.7 grams of water?

Chemistry

1 answer:

Anika [276]2 years ago

8 0

Answer:

This part require data such as Avogadro's number and the molar mass of water. But first, let's find the mass of water in the specified volume by making use of the density formula:

Density = mass/volume

1 g/mL = Mass/70 mL

Mass = 70 g

Each water contains 18 grams per mole, and each mole contains 6.022×10²³ molecules of water. Thus,

70 g * 1mole/18 g * 6.022×10²³ molecules/mole = 2.342×10²⁴ molecules of water

Explanation:

You might be interested in

2. When liquid water freezes, it tends to

pshichka [43]

Expand…
hope this helps

4 0

3 years ago

CC14

maria [59]

Answer:

Na and Cl

Explanation:

An ionic compound is solid at state room temperature. Therefore Na and Cl would be the correct answer :)

5 0

3 years ago

I took 100 micrograms of vitamin d yesterday (13yrs old) is it bad

Amanda [17]

Answer:

take 75 gm or it will be overdose

6 0

2 years ago

It increases with. And

sp2606 [1]

Yessss sirrrrrrrrrrr

4 0

3 years ago

The mole fraction of a non-electrolyte (MM 40.0 g/mol) in a saturated aqueous solution is 0.310. What is the molality of the sol

jeka57 [31]

<u>Answer:</u> The molality of non-electrolyte is 24.69 m

<u>Explanation:</u>

We are given:

Mole fraction of saturated aqueous solution = 0.310

This means that 0.310 moles of non-electrolyte is present.

Moles of water (solvent) = 1 - 0.310 = 0.690 moles

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of water = 0.690 moles

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

$0.690mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.690mol\times 18g/mol)=12.42g$

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{n_{solute}\times 1000}{W_{solvent}\text{ (in grams)}}$

Where,

$n_{solute}$ = Moles of solute (non-electrolyte) = 0.310 moles

$W_{solvent}$ = Mass of solvent (water) = 12.42 g

Putting values in above equation, we get:

$\text{Molality of non-electrolyte}=\frac{0.310\times 1000}{12.42}\\\\\text{Molality of non-electrolyte}=24.96m$

Hence, the molality of non-electrolyte is 24.69 m

4 0

3 years ago