Answer:
6.217 pounds
Explanation:
We are given;
- Density of body fats 0.94 g/mL
- Volume of fats removed = 3.0 L
We are required to determine the mass of fats removed in pounds.
We need to know that;
Density = Mass ÷ volume
1 L = 1000 mL, thus, volume is 3000 mL
Rearranging the formula;
Mass = Density × Volume
= 0.94 g/mL × 3000 mL
= 2,820 g
but, 1 pound = 453.592 g
Therefore;
Mass = 2,820 g ÷ 453.592 g per pound
= 6.217 pounds
Thus, the amount of fats removed is 6.217 pounds
They are gases at room temperature
Hope this helps:)
<span>Step 1 is to determine the mass of each part
Mass of Ca is 40.08 g
Mass of C is 12.01 g
Mass of O is 16.00 x 3 = 48.00 g
Step 2 is to determine the total mass of the compound
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g
Step 3 is to determine the % of each part using the following formula:
Mass of part / total mass x 100 =
40.08 / 100.09 x 100 = 40.04 % Ca
12.01 / 100.09 x 100 = 12.00 % C
48.00 / 100.09 x 100 = 47.96 % O
Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :)
40.04
+12.00
+47.96
=100.00</span><span>
</span>
