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3 years ago

Why Ammonia is nut dried by passing through concentrated H2SO4.

Chemistry

1 answer:

STALIN [3.7K]3 years ago

6 0

Answer:

Because it is absorbed by conc . H . SO , to form ammonium sulphate.

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What is the difference between Polar and Non-Polar molecules?

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2 years ago

Is the entropy change favorable or not, when a nonpolar molecule is transferred from water to a nonpolar solvent?

jonny [76]

Answer:

Entropy change is favorable when a nonpolar molecule is transferred from water to a nonpolar solvent.

Explanation:

A nonpolar molecule is not miscible in water (polar solvent). Therefore, when mixed together, each specie will cluster together and solvation will not happen.

However, when you tranfer the nonpolar molecule to a nonpolar solvent, the solvent molecules will interact with the nonpolar molecule. This will increase entropy as the level of disorder will increase with solvation.

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3 years ago

What step usually comes last when solving numeric problems

Lilit [14]

No mathematics the most common way of solving an equation will be PEMDAS so the answer for your question will most likely be subtraction.

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3 years ago

A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at

weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of tin = $m_1=18.5 g$

Specific heat capacity of tin = $c_1=0.21 J/g^oC$

Initial temperature of the tin = $T_1=97.38^oC$

Final temperature = $T_2$ =T

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=75.7 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=21.52^oC$

Final temperature of water = $T_2$ =T

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)$

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

5 0

3 years ago

oth hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you opene

Ksju [112]

Answer: Odor of ammonia would we detect first on the other side of the room.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{M_{NH_3}}{M_{H_2S}}}$

$\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{17.031}{34.1}}$

$\frac{Rate_{H_2S}}{Rate_{NH_3}}=0.71$

Thus the odor of ammonia would we detect first on the other side of the room as the rate of effusion of ammonia would be faster as it has low molecular weight as compared to hydrogen sulphide.

5 0

3 years ago

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Why Ammonia is nut dried by passing through concentrated H2SO4.​

Why Ammonia is nut dried by passing through concentrated H2SO4.