Answer:
D
Explanation:
To answer this question, we will need to write the dissociation equation of aluminum trichloride.
AlCl3 ——-> Al3+ + 3Cl-
It can be seen that when aluminum chloride dissociates, it gives one mole of aluminum ion and three moles of the chloride ion.
From here we can see that the concentration of the aluminum chloride equals that of the aluminum ion while that of the chloride ion is thrice that of the aluminum chloride. This means we simply multiply 0.12M by 3 to get the molarity of the chloride ion while that of the aluminum ion remains the same
Answer:
1. None of these have hydrogen bonding.
2. None of these have dipoles.
3. Bigger molecules will have stronger London dispersion forces. So I2 has the strongest forces,
and F2 will have the weakest. Correspondingly, I2 will have the highest boiling point and F2 will have the lowest boiling point.
Answer: F2, Cl2, Br2, I2
Explanation:
The volume of the sample after the reaction : V₂=5.484 L
<h3>Further explanation</h3>
Given
Reaction
2HBr(g) + Cl2(g) => 2HCl (g)+Br2(g)
0.1100 mol of HBr(g)
5x10⁻² mol of Cl2(g)
Required
The volume of the sample after reaction
Solution
Find limiting reactant :
0.11/2 : 0.05/1 = 0.055 : 0.05
Limiting reactant : Cl₂
mol Products based on mol Cl₂
mol products = mol HCl + mol Br₂
mol products = 2/1x0.05 + 1/1x0.05
mol products = 3 x 0.05 = 0.15
mol reactants = 0.11 + 0.05 = 0.16
<em>From Avogadro's law, </em>
In the same T, P, and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
V₁/n₁=V₂/n₂
1 = reactants, 2 = products
Input the value :
5.85/0.16=V₂/0.15
V₂=5.484 L
Answer:
2–methylpropene.
Explanation:
To successfully name the compound given in the question, we must observe the following:
1. Determine the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached and locate it's position by giving it the lowest possible count.
4. Combine the above to obtain the name of the compound.
Now, let us determine the name of the compound. This is illustrated below:
1. The functional group of the compound is the double bond i.e the compound is an alkene.
2. The longest continuous carbon chain is 3 i.e propene since it is an alkene.
3. The substituent group attached is methyl i.e CH3. In this case, we'll start counting from the side of the double bond being the functional group. Therefore, the methyl group i.e CH3 is at carbon 2.
4. Therefore, the name of the compound is:
2–methylpropene
