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Novay_Z [31]
3 years ago
7

Challenge question: This question is worth 6 points. As you saw in problem 9 we can have species bound to a central metal ion. T

hese species are called ligands. In the past we have assumed all the d orbitals in some species are degenerate; however, they often are not. Sometimes the ligands bound to a central metal cation can split the d orbitals. That is, some of the d orbitals will be at a lower energy state than others. Ligands that have the ability to cause this splitting are called strong field ligands, CN− is an example of these. If this splitting in the d orbitals is great enough electrons will fill low lying orbitals, pairing with other electrons in a given orbital, before filling higher energy orbitals. In question 7 we had Fe2+, furthermore we found that there were a certain number (non-zero) of unpaired electrons. Consider now Fe(CN)6 4−: here we also have Fe2+, but in this case all the electrons are paired, yielding a diamagnetic species. How can you explain this?
Chemistry
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

CN^- is a strong field ligand

Explanation:

The complex, hexacyanoferrate II is an Fe^2+ specie. Fe^2+ is a d^6 specie. It may exist as high spin (paramagnetic) or low spin (diamagnetic) depending on the ligand. The energy of the d-orbitals become nondegenerate upon approach of a ligand. The extent of separation of the two orbitals and the energy between them is defined as the magnitude of crystal field splitting (∆o).

Ligands that cause a large crystal field splitting such as CN^- are called strong field ligands. They lead to the formation of diamagnetic species. Strong field ligands occur towards the end of the spectrochemical series of ligands.

Hence the complex, Fe(CN)6 4− is diamagnetic because the cyanide ion is a strong field ligand that causes the six d-electrons present to pair up in a low spin arrangement.

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How does a substances temperature change when the average kinetic energy of its particles increases ? When the average kinetic e
Novay_Z [31]

Answer:

The temperature of a substance when the average kinetic energy of its particles increases and decreases when the average kinetic energy decreases.

Explanation:

Atoms and molecules are in constant motion. Kinetic energy is a form of energy, known as energy of motion. Kinetic energy is a form of energy, known as energy of motion. The kinetic energy of an object is that which is produced due to its movements, which depends on its mass (m) and speed (v).

Temperature refers to a quantity used to measure the kinetic energy of a system. That is, temperature is defined as an indicator of the average kinetic energy of the particles in a body.

So, since temperature is a measure of the speed with which they move, the higher the temperature the faster they move.

Finally, <u><em>the temperature of a substance when the average kinetic energy of its particles increases and decreases when the average kinetic energy decreases.</em></u>

8 0
3 years ago
Under identical conditions of temperature and pressure, which of the following gasses is the densest: Ne, CO2, or Cl2?
Tanzania [10]
Cl2=3.17g/L
Ne=.901g/L
CO2=1.96g/l
 therefore Cl2 is the densest gas under the given conditions.
7 0
2 years ago
Need help with this question
Liula [17]

Answer:

I think it's c

Explanation:

I hope this helps :)

3 0
3 years ago
Read 2 more answers
Why is a changing ocean temperature of only one or 2 degrees so concerning?
gregori [183]
<span>One degree Celsius indicates the same temperature change as one </span>
7 0
3 years ago
How can you simulate the radioactive half-life of an element?
ch4aika [34]

Answer:

TRIAL 1:

For “Event 0”, put 100 pennies in a large plastic or cardboard container.

For “Event 1”, shake the container 10 times. This represents a radioactive decay event.

Open the lid. Remove all the pennies that have turned up tails. Record the number removed.

Record the number of radioactive pennies remaining.

For “Event 2”, replace the lid and repeat steps 2 to 4.

Repeat for Events 3, 4, 5 … until no pennies remain in the container.

TRIAL 2:

Repeat Trial 1, starting anew with 100 pennies.

Calculate for each event the average number of radioactive pennies that remain after shaking.

Plot the average number of radioactive pennies after shaking vs. the Event Number. Start with Event 0, when all the pennies are radioactive. Estimate the half-life — the number of events required for half of the pennies to decay.

Explanation:

6 0
2 years ago
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