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MA_775_DIABLO [31]
2 years ago
6

Three tennis balls are packaged in a box. The box is 12.1 cm long, 3.5 cm wide, and 3.5 cm tall. Each ball is 3.3 cm in diameter

. What is the approximate volume of the empty space in the box rounded to the nearest tenth? Use 3.14 = π. (volume of the box = length times width times height) SHOW YOUR WORK.
Mathematics
1 answer:
valkas [14]2 years ago
5 0

Answer:

134 cm^3 empty space

Step-by-step explanation:

The box has a total volume of (12.1)(3.5)(3.5) = 191 cm^3

Each ball has a volume of (4/3)πr³

The ball's diameter is 3.3 cm, so it's radius is (3.3/2) or 1.65 cm

(4/3)(3.14)(1.65)³ = 18.8 cm^3

There are 3 balls, so they occupy 3*18.8 or 56.4 cm^3

Box volume - volume of 3 balls

191 cm^3    -   56.4 cm^3 = 134 cm^3

134 cm^3 is empty space in the box.

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