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2 years ago

5

What’s the force of a pitching machine on a baseball?

1 answer:

worty [1.4K]2 years ago

7 0

Answer:

The Machine exerts a force of 9N.

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 30 m/s

Time (t) = 0.5 s

Acceleration (a) = (v-u)/t

= (30-0)/0.5 m/s²

= 30/0.5 m/s²

= 60 m/s²

Mass = 0.15 kg

Force = Mass*Acceleration

= 0.15*60 N

= 9 N

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2.92 A 50.0-g silver object and a 50.0-g gold object are both added

Trava [24]

Answer:

82.9 mL

Explanation:

1. Volume of silver

$\begin{array}{rcl}\text{Density}&=& \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho&=& \dfrac{m}{V}\\\\V &=& \dfrac{m}{\rho}\\\\& = & \dfrac{\text{50.0 g}}{\text{10.49 g$\cdot$mL}^{-1}}\\\\& = & \text{4.766 mL}\\\end{array}\\\text{The volume of the silver is $\large \boxed{\textbf{4.766 mL}}$}$

2. Volume of gold

$\begin{array}{rcl}V& = & \dfrac{\text{50.0 g}}{\text{19.30 g$\cdot$mL}^{-1}}\\\\& = & \text{2.591 mL}\\\end{array}\\\text{The volume of the gold is $\large \boxed{\textbf{2.591 mL}}$}$

3. Total volume of silver and gold

V = 4.766 mL + 2.591 mL = 7.36 mL

4 New reading of water level

V = 75.5 mL + 7.36 mL = 82.9 mL

3 0

4 years ago

Question 7 of 32

Sever21 [200]

Answer:O D to protect the environment from harmful chemicals

Explanation:

3 0

4 years ago

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Scientists, emergency personnel, and the weather service keep a close eye on this potential natural disaster that impacts Florid

Usimov [2.4K]

Answer:

hurricane

Explanation:

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3 years ago

Which of these is a way that bio stimulation can be used ?

Aneli [31]

Answer:

To combat the spread of invasive species

hope that helped <3

6 0

3 years ago

Glucose (C6H12O6)(C6H12O6) can be fermented to yield ethanol (CH3CH2OH)(CH3CH2OH) and carbon dioxide (CO2).

zhenek [66]

Answer: a) 49.8 gram

b) 47.0 %

Explanation:

First we have to calculate the moles of glucose

$\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles$

The balanced chemical reaction will be,

$C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2$

From the balanced reaction, we conclude that

As,1 mole of glucose produce = 2 moles of ethanol

So, 0.54 moles of glucose will produce = $\frac{2}{1}\times 0.54=1.08$ mole of ethanol

Now we have to calculate the mass of ethanol produced

$\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}$

$\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g$

Now we have to calculate the percent yield of ethanol

$\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%$

Therefore, the percent yield is 47.0 %

7 0

3 years ago