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Tresset [83]
3 years ago
14

If you want 370 mL of 2.3 M AgNO3 solution, how many grams of AgNO3 do you need?

Chemistry
1 answer:
Allisa [31]3 years ago
8 0

dont use that link its bad

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Please help! <br> Answer please!
padilas [110]

Answer: a

Explanation: a

8 0
3 years ago
According to kinetic-molecular theory, which of the following would not be considered an ideal gas? Check all that apply.
Vikki [24]

Answer:

are a gas at very low volumes, when gas particles are very close together

a gas at very low temperatures, when gas particles have very little kinetic energy

a gas with highly polar molecules that have very strong intermolecular forces

Explanation:

4 0
4 years ago
Read 2 more answers
The half life for the decay of carbon-14 is 5.73 x 10 years. Suppose the activity due to the radioactive decay of the carbon-14
Elena-2011 [213]

Answer:

Age of the atifact is 4.2\times 10^{2} years

Explanation:

  • For first -order radioactive decay- A_{t}=A_{0}(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}
  • A_{t} represents activity of radioactive nuclide after t time, A_{0} represents initial activity of radioactive nuclide and t_{\frac{1}{2}} represents half-life
  • Here, A_{t}=19Bq, A_{0}=20Bq and t_{\frac{1}{2}}=5.73\times 10^{3}years

Plug-in all the given values in the above equation-

19=20\times (\frac{1}{2})^{\frac{t}{5.73\times 10^{3}}}

or, t=4.2\times 10^{2}

So, age of the atifact is 4.2\times 10^{2} years

6 0
3 years ago
What volume of concentrated (10.2 M) HCl would be required to prepare 1.11 x 104 mL of 1.5 M HC1? Enter your answer in scientifi
Tomtit [17]

Answer:

The required volume is 1.6 x 10³mL.

Explanation:

When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:

C₁ . V₁ = C₂ . V₂

where,

C₁ and V₁ are the concentration and volume of the concentrated solution

C₂ and V₂ are the concentration and volume of the dilute solution

In this case, we want to find out V₁:

C₁ . V₁ = C₂ . V₂

V_{1} = \frac{C_{2}.V_{2}}{C_{1}} = \frac{1.5M \times1.11.10^{4}mL }{10.2M} =1.6\times10^{3} mL

3 0
4 years ago
Identify the solute and solvent in a solution made from 15 mL of oxygen and 5 mL of helium.
Marina CMI [18]

Answer:

Oxygen is solvent and Helium is solute.

Explanation:

Helium is a complety inert gas which do not react with other compounds whereas, oxygen can take part in chemical reaction with many compounds.

  • if we mix 15 mL of oxygen and 5mL of helium then the oxygen is the solvent and helium is solute.
  • In a mixture the compound with the greater volume is solvent and the compound with lwss volume is solute.
  • in this case, oxygen has greater volume than that of helium so oxygen is solute and helium is solvent here.
6 0
3 years ago
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