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julia-pushkina [17]
4 years ago
13

The speedometer on a car actually measures the rotational speed of the axle and converts that to the linear speed of the car, as

suming the car’s tires diameter is 0.62 m. What is the rotational speed of the axle when the car is traveling 20 m/s?
Physics
2 answers:
Studentka2010 [4]4 years ago
8 0
             <span> (26 m/s)(1 rotation/0.62π m) ≈ 13.35 rotations/s that will do pig that'll do</span>
Lady_Fox [76]4 years ago
7 0

Explanation :

It is given that,

The diameter of the car's diameter, d = 0.62 m

Radius, r = 0.31 m

Speed of the car, v = 20 m/s

We know that the relation between the angular velocity and linear velocity is given by :

v=r\omega

Where \omega is angular velocity

\omega=\dfrac{v}{r}

\omega=\dfrac{20\ m/s}{0.31\ m}

\omega=64.5\ rotations/sec

Hence, this is the required solution.

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Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He travels at a steady 46.0 mph . Beth leaves Los A
elena-14-01-66 [18.8K]

Answer:

25 min, 48 sec

Explanation:

Alan:

t = d/v

  = 400 mi / 46 mph = 8.70 hr

So it took Alan 8.70 hrs; from 8 am, that's 4:42 pm that he arrives.

t = d/v

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So it took Beth 7.27 hrs; from 9 am, that's 4:16:12 that she arrives.

4:42 - 4:16:12 = 25.8 minutes = 25 minutes, 48 sec

4 0
4 years ago
An incline plane has Ф = 40.0° and μ k = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m
lesya [120]
     The block on the action of two forces, the Force of Friction and the Tangential Weight. Using the Newton's Secound Law, we have:

P_{t}-Fat=ma \\ mgsen\O-mgucos\O=ma \\ a=g(sen\O-ucos\O)
 
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\Delta t= \frac{V}{g(sen\O-ucos\O)} \\ \Delta t= \frac{12}{10(sen40^o-0.15cos^o)}  \\ \Delta t= \frac{12}{10(0,64-0.15x0.77)}  \\ \Delta t= \frac{12}{5.27}  \\ \boxed {\Delta t=2.28s}

Obs: Approximate results

If you notice any mistake in my english, please let me know, because i am not native.

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8 0
2 years ago
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Answer:

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