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BlackZzzverrR [31]
4 years ago
12

For installation with a 25-kVA, 3-phase transformer, a 440-volt primary, and a 120-volt secondary. Calculate the maximum overcur

rent protection value (not the fuse or circuit breaker rating) using the protection method for primary-only protection. (Round the FINAL answer to two decimal places.)
Physics
1 answer:
andre [41]4 years ago
4 0

Answer:

41.053 A

Explanation:

given,

three phase kVA = 25-kVA

voltage = 440 Volt

current = ?

To determine three phase kVA when volts and amperes are know

   three phase kVA = 1.73 x V x I

    I = \dfrac{three\ phase\ kVA}{1.73 \times V}

    I = \dfrac{25000}{1.73 \times 440}

           I = 32.84 A

the maximum overcurrent protection value is equal to

            = 125 % of I

            = 1.25 x 32.84

            = 41.053 A

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Answer:

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General Formulas and Concepts:

<u>Dynamics</u>

Newton's Law of Motions

  • Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
  • Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
  • Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u> </u>

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] F = 22000 N

[Given] m = 1375 kg

[Solve] a

<u>Step 2: Find Acceleration</u>

  1. Substitute in variables [Newton's 2nd Law of Motion]:                                 22000 N = (1375 kg)a
  2. Isolate <em>a</em>:                                                                                                            16 m/s² = a
  3. Rewrite:                                                                                                             a = 16 m/s²
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