Answer:
The transverse component of acceleration is 26.32
where as radial the component of acceleration is 8.77 
Explanation:
As per the given data
u=π/4 rad
ω=u'=2 rad/s
α=u''=4 rad/s

So the transverse component of acceleration are given as

Here


So

The transverse component of acceleration is 26.32 
The radial component is given as

Here

So

The radial component of acceleration is 8.77 
In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
And because the problem requires that we use only 2 significant figures,
F=13N
Therefore, the student must exert 13N of force.
I believe it would be choice A. but not 100% possitive
Answer:
DONTKNOW NEED CAREER FILD FIRST TO ANWSER
Explanation:
The answer is the change in kinetic energy
K = 1/2 • mv^2
Change in K = (1/2 • 20 • 10^2) - (1/2 • 20 • 5^2)
Change in K = 1000 - 250 = 750J