Answer:
= 26.94 m/s
Explanation:
given,
angle of inclination = 30°
mass of the sleigh = 200 kg
coefficient of kinetic friction = 0.2
height of inclination = 10 m
pull force be = 5000 N
now,.
T - f_s - mg sin \theta = m aT−f
s
−mgsinθ=ma
T - \mu N - mg sin \theta = m aT−μN−mgsinθ=ma
T - \mu mg - mg sin \theta = m aT−μmg−mgsinθ=ma
a = \dfrac{T}{m} - \mu g - g sin \thetaa=
m
T
−μg−gsinθ
a = \dfrac{5000}{200} - \0.2\times 9.8 - 9.8 \times sin 30^0a=
200
5000
−\0.2×9.8−9.8×sin30
0
a = 18.14\ m/s^2a=18.14 m/s
2
L = \dfrac{10}{sin 30}L=
sin30
10
L = 20 m
v² = u² + 2 as
v² = 0 + 2 x 18.14 x 20
v = 26.94 m/s
Answer:
Explanation:
It is given that,
Mass of the car, m = 763 kg
Speed of the car, v = 26 m/s
Mass of the iron, m' = 15 kg
Specific heat of iron, c = 450 J/kg
When the car is in motion, it will possess kinetic energy. It is given by :
K = 257894 J
Since, energy is absorbed by the brakes. The kinetic energy of the car is absorbed by the brakes. So,
is the increase in temperature of the brakes
So, the increase in temperature of the brakes is 38.20 degrees Celsius. Hence, this is the required solution.
I can't think of any way that pressure can be decreased due to added pressure.
Be that as it may, and it certainly still is ...
No matter what you do to the pressure or the temperature of
the gas in that tank, the volume doesn't change. Any sample
of gas always expands to fill the container in which it's confined.
Its volume doesn't change until you either transfer it to another
container with different volume, or else change the volume of
the container it's in.
The scientist who suggested that atoms contain a hard core containing most of the mass of an atom was Ernest Rutherford.
3500/ 100 = 35
the answer is 35m!
