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Gnom [1K]
2 years ago
10

What is the classification of each system? Drag the answers into the boxes to match each system. {4x−2y=102x−y=5 {y=2x−3−2x y=−5

{2x−5y=143x 4y=10.
Mathematics
1 answer:
Rus_ich [418]2 years ago
6 0

1.   4x − 2y = 10 and 2x − y = 5

Lines are coincident.

2.  y = 2x − 3 and −2x + y = −5

Lines are parallel.

3.  2x − 5y = 14  and 3x + 4y = 10

Lines are intersecting.

<h2>Linear system</h2>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

<h3>Given</h3>

1.   4x − 2y = 10 and 2x − y = 5

2.  y = 2x − 3 and −2x + y = −5

3.  2x − 5y = 14  and 3x + 4y = 10

<h3>Condition for the lines.</h3>

\rm \dfrac{a_1}{a_2} \neq  \dfrac{b_1}{b_2} \ \ \ \ \ \ \ \ \ \ \ Lines\ are\ intersecting\\\\\rm \dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} \neq  \dfrac{c_1}{c_2}\ \ \ \  Lines \ are\ parallel\\\\\rm \dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} = \dfrac{c_1}{c_2} \ \ \ \  Lines\ are\ coincident

<h3>Drag the answers into the boxes to match each system.</h3>

1.   4x − 2y = 10 and 2x − y = 5

Lines are coincident.

2.  y = 2x − 3 and −2x + y = −5

Lines are parallel.

3.  2x − 5y = 14  and 3x + 4y = 10

Lines are intersecting.

More about the linear system link is given below.

brainly.com/question/20379472

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Answer:

No

Step-by-step explanation:

No because (1,2) falls on the line, and the line is a dotted line, which means that any point on the line is not a solution to the inequality.

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2 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
What is the value of log^625^5<br>​
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need to get the left side to equal the right side. Keeping the right side alone and not changing it.
likoan [24]

<u>To prove the trigonometric equation:</u>

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

RHS=(\sin x+\cos x)(1-\sin x \cos x)

We know that \sin^2x +\cos^2x=1, substitute this in place of 1.

       =(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)

Multiply each term of the first term with each term of the 2nd term.

       =\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x

Group like terms together.

       =\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x

       =\sin^3x +( 0)+(0) + \cos^3 x

       =\sin^3x + \cos^3 x

       = LHS

RHS = LHS

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

Hence proved.

7 0
3 years ago
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