3+
So, compounds of boron contain boron in a positive oxidation state, generally +3. The sum of oxidation numbers of all constituent atoms of a given molecule or ion is equal to zero or the charge of the ion, respectively. ... In most of the stable compounds of boron, its oxidation number is +3
Answer: I think the answer is 2.5 M.
Explanation: Formula: M = n/v
M= 10 mol / 4L
M= 2.5 M
B I hope it’s right I don’t really help a lot but yeah lol
Answer:
Kb for CH₃NH₂ (methylamine) is 4.4 × 10⁻⁴
Hope that helps.
