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Studentka2010 [4]
3 years ago
15

Please help! Will mark best answer!!

Physics
2 answers:
MA_775_DIABLO [31]3 years ago
7 0
The answer is (A) hope it helps 
ICE Princess25 [194]3 years ago
7 0
Hey there Chainsmokers! 

A nuclear fusion would actually be known to be a (reaction) of a very low fuse. Which on this case, it would then carry alot of energy, why? This would happen because the fuse would then form heavier substances such as nucleas.

So, from looking at your options listed above, it would seem that the correct answer would be your option "a".

"the process of two or more atomic particles sticking together to form a heavier atomic nucleus.".

Your correct answer would be option a.)

Hope this helps you dear!


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A 2.37-kg rock is released from rest at a height of 22.2 m. ignore air resistance and determine (a) the kinetic energy at 22.2 m
marta [7]
Yes yes yes yes yes yes 
8 0
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Oceanic water particles mainly move in circles; is this movement greater on the ocean's surface or below the surface? Explain yo
goblinko [34]
I think that the oceanic water particles mainly move in circles greater in the oceans surface because of how big the waves can be and how wind and air impact the motion. The water particles move more on the surface because of the other factors that impact it such as people, wind, air, etc...
5 0
3 years ago
The work function of an element is the energy required to remove an electron from the surface of the solid. The work function fo
vichka [17]

Answer:

λ = 548.7 nm

Explanation:

Hi!

First we want to know how much energy we need to remove 1 electron from the surface of the solid:

218.1 kJ/mol => 218 100 J / (6.022 x 10^23) electrons

                             = 3.621 x 10^-19 J/electron  

That is we need 3.621 x 10^-19 J to remove one electron

Now we can calculate the wavelength that a photon must have in order to have this energy:

E = (hc) / λ

λ = (hc) / Ε

where

 h = 6,626070150(69) ×10 -34 Js (wikipedia)

 c = 3 x10^8 m/s

hc = 1.987 x 10^-25 Jm

Therefore:

λ = ( 1.987 x 10^-25 /3.621 x 10^-19 ) m = 5.487 x 10^-7 m

λ = 548.7 nm

4 0
3 years ago
A boy finds an abandoned mine shaft in the woods, and wants to know how deep the hole is. He drops in a stone, and counts 4 seco
Shalnov [3]

The shaft is 78m approximately deep. The correct option is D which is 78 meters

<h3>What are Sound Waves ?</h3>

Sound waves are longitudinal. That is, the direction of the waves is parallel to the direction of its propagation of particles.

Given that a boy finds an abandoned mine shaft in the woods, and wants to know how deep the hole is. He drops in a stone, and counts 4 seconds before he hears the "plunk" of the stone hitting the bottom of the shaft.

  • The speed of the sound V = 330m/s
  • The time it takes the sound to reach the top = t

Speed V = distance / time

330 = h/t

Make t the subject of formula

t = h/330

As the stone is dropped, initial velocity = 0, Using the formula

h = 1/2gT²

But T = 4 - t

T = 4 approximately

Substitute all the parameters

h = 1/2 × 9.8 × (4)²

h = 4.9 × (16)

h = 78.4m

Therefore, the shaft is 78m approximately deep. The correct option is D which is 78 meters

Learn more about sound wave here: brainly.com/question/16093793

#SPJ1

3 0
2 years ago
What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?
IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as m_{1} \ and\ m_{2}\ respectively

Let\ m_{1} =1 kg\ and\ m_{2} =2 kg

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

                             m_{1} g-T=m_{1} a        [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction [\mu]=0.13

Hence\ the\ frictional\ force\ F=\mu N

                                                     F=\mu m_{2} g

Hence the net force acting on the body having mass 2 kg-

                                  T-\mu m_{2} g=m_{2} a  [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

                           m_{1} g-T=m_{1}a             [1]

                           T-\mu m_{2}g= m_{2} a   [2]

                           ---------------------------------------------------

                           [m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a

                           a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g

                           a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2

                           a=\frac{0.74}{3} *9.8\ m/s^2

                           a=2.417 m/s         [ans]

6 0
3 years ago
Read 2 more answers
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