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Advocard [28]
2 years ago
11

Help please!

Physics
1 answer:
Talja [164]2 years ago
3 0

The correct expression for the maximum speed of the object during its motion is \frac{FT}{m}.

<h3>Maximum speed of the object</h3>

The maximum speed of the object is determined using the following formulas;

v(max) = Aω

where;

  • A is the amplitude of the motion
  • ω is angular speed

The maximum speed of the object can also be obtained from the maximum net force on the object,

F = ma

where;

  • F is the maximum net force
  • a is the acceleration
  • m is mass of the object

F = m(v/t)

mv = Ft

v = Ft/m

Thus, the correct expression for the maximum speed of the object during its motion is \frac{FT}{m}.

Learn more about maximum speed here: brainly.com/question/4931057

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Here, you need to use your "Protractor" as it is given in the question, but we can calculate the value with the help of our mathematical calculation too:
[ Protractor can be use only in real life, not here ]

Draw an imaginary line from initial position to final position.
Now, In that triangle, tan x = P/B
tan x = 1.4 / 2
tan x = 0.70
x = tan⁻¹ (0.70)
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In short, Your Answer would be 35 degrees

Hope this helps!
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3 years ago
What are the two types of magnets?
xeze [42]
Negative and positive
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4 years ago
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Primary sources are most often produced around the time of the events you are studying.


hopwe this helps

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4 years ago
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(a) Calculate the self-inductance of a solenoid that is
adell [148]

Answer:

a) 0.142mH

b) 14mV

Explanation:

the complete answer is:

(a) Calculate the self-inductance of a solenoid that is <ghtly wound with wire of diameter 0.10 cm, has a cross-sec<onal area of 0.90 cm2 , and is 40 cm long. (b) If the current through the solenoid decreases uniformly from 10 to 0 A in 0.10 s, what is the emf induced between the ends of the solenoid

a) the self inductance of a solenoid is given by:

L=\frac{\mu_o N^2 A}{L}

μo: magnetic permeability of vacuum = 4\pi*10^{-7}N/A^2

A: cross sectional area = 0.9cm^2=9*10^{-5}m

L: length of the solenoid = 40cm = 0.4m

The N turns of the wire is calculated by using the diameter of the wire:

N = (40cm)/(0.10cm)=400

By replacing in the formula you obtain:

L=\frac{(4\pi *10^{-7}N/A^2)(400)^2(9*10^{-5}m^2))}{(0.4m)}=1.42*10^{-4}H

the self inductance is 1.42*10^{-4}H = 0.142mH

b) to find the emf you can use:

emf=L\frac{\Delta I}{\Delta t}=(1.42*10^{-4}H)\frac{10A-0A}{0.10s}=0.014V=14mV

the emf induced is 14mV

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3 years ago
Which scientist used Tycho Brahe’s data to propose three laws of planetary motion?
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