Using the combined gas law of P1V1=P2V2 and plug it in you get (4)V1 for you don't have initial volume = (0.2)(500) --> 4V1=100, divide by the coefficient on both sides and you get V1=25
The answer to this would be C
Answer:
The work done is 12 MJ.
Explanation:
The engine of a car exerts a constant traction force of F=4000N . Assume that the car is moving at a constant speed of 36 km/hr. In five minutes, what is the work done by the engine's traction?
Force, F = 4000 N
speed, v = 36 km/h = 10 m/s
time , t = 5 minutes = 5 x 60 = 300 s
Work done is given by
W = force x distance
W = 4000 x 10 x 300 J = 12 x 10^6 J = 12 MJ
Answer:
Explanation:
there are many, many charge carriers moving directly throughout the entire length of the circuit. Current is that the rate at which charge crosses some extent on a circuit. A high current is that the results of several coulombs of charge crossover a cross section of a wire on a circuit. If the charge carriers are densely packed into the wire, then there doesn't need to be a high speed to possess a high current. That is, the charge carriers don't need to travel an extended distance during a second, there just has got to be tons of them passing through the cross section.
-- 4.5 minutes lasts 270 seconds
-- the case covers 15m in each sec
-- its total distance is
(15 m/s) x (270 sec) = 4,050 meters
