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allochka39001 [22]
3 years ago
8

Which item is necessary to make an electromagnet? Question 4 options: Render of a wooden cube with sharp edges, coordinating pat

terns and fine wood texture. Minimal shadow and reflection. Copper Wire Electrical switch assessment graphic Green plastic spoon.
Physics
1 answer:
BlackZzzverrR [31]3 years ago
4 0

The electromagnet is a device that requires conducting wires wrapped around the iron core.

For making an electromagnet, the most necessary item is a copper wire.

What is an Electromagnet?

An electromagnet is a device that has conducting wires wrapped around an iron core. When electricity is passed through the wires, a magnetic field is generated. The setup acts as a strong magnet.

In order to make an electromagnet, a current-carrying wire is needed to wrap around a magnetic material. The current-carrying wires will play the role of conducting wires and the conducting wires are necessary to make an electromagnet. These wires can be made of copper.

Thus, we can conclude that for making an electromagnet, the most necessary item is a copper wire.

Learn more about the electromagnet here:

brainly.com/question/10060657

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Answer:The temperature of a piece of Metal X with a mass m of 95.4g increases from 25.0°C to 48.0°C as the metal absorbs 849 J of heat.

Explanation:

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2 years ago
___ acceleration occurs when an object speeds up
AleksandrR [38]

Explanation:

Acceleration is defined as the change in velocity over time.

When there is an increment or increase in the magnitude of velocity of a moving body then it is known as positive acceleration.

Whereas when there is a decrease in magnitude of velocity of a moving body then it is known as negative acceleration.

Thus, we can conclude that positive acceleration occurs when an object speeds up.

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3 years ago
Read 2 more answers
Compare and contrast light waves and sound waves
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4 0
3 years ago
Blocks A (mass 2.00 kg) and B (mass 6.00 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block
Oksana_A [137]

Answer:

av=0.333m/s, U=3.3466J

b.

v_{A2}=-1.333m/s,\\ v_{B2}=0.667m/s

Explanation:

a. let m_A be the mass of block A, andm_B=10.0kg be the mass of block B. The initial velocity of A,\rightarrow v_A_1=2.0m/s

-The initial momentum =Final momentum since there's no external net forces.

pA_1+pB_1=pA_2+pB_2\\\\P=mv\\\\\therefore m_Av_A_1+m_Bv_B_1=m_Av_{A2}+m_Bv_{B2}

Relative velocity before and after collision have the same magnitude but opposite direction (for elastic collisions):

v_A_1-v_B_1=v_{B2}-v_{A2}

-Applying the conservation of momentum. The blocks have the same velocity after collision:

v_{B2}=v_{A2}=v_2\\\\2\times 2+10\times 0=2v_2+10v_2\\\\v_2=0.3333m/s

#Total Mechanical energy before and after the elastic collision is equal:

K_1+U_{el,1}=K_2+U_{el,2}\\\\#Springs \ in \ equilibrium \ before \ collision\\\\U_{el,2}=K_1-K_2=0.5m_Av_A_1^2-0.5(m_A+m_B)v_2^2\\\\U_{el,2}=0.5\times 2\times 2^2-0.5(2+10)(0.333)^2\\\\U_{el,2}=3.3466J

Hence, the maxumim energy stored is U=3.3466J, and the velocity=0.333m/s

b. Taking the end collision:

From a above, m_A=2.0kg, m_B=10kg, v_A=2.0,v_B_1=0

We plug these values in the equation:

m_Av_A_1+m_Bv_B_1=m_Av_{A2}+m_Bv_{B2}

2\times2+10\times0=2v_A_2+10v_B_2\\\\2=v_A_2+5v_B_2\\\\#Eqtn 2:\\v_A_1-v_B_1=v_{B2}-v_{A2}\\\\2-0=v_{B2}-v_{A2}\\\\2=v_{B2}-v_{A2}\\\\#Solve \ to \ eliminate \ v_{A2}\\\\6v_{B2}=2.0\\\\v_{B2}==0.667m/s\\\\#Substitute \ to \ get \ v_{A2}\\\\v_{A2}=\frac{4}{6}-2=1.333m/s

7 0
4 years ago
6. A car drives 750 miles in 10 hours. Calculate the speed of the truck<br><br><br> .
Dmitriy789 [7]

Answer:

75 miles an hour

I hope this is correct and helps

3 0
3 years ago
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