To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.
CF₂Cl₂ is a refrigerant. When it is evaporated, it absorbs heat from water, which cools.
<h3>What is evaporation?</h3>
Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase.
- Step 1: Calculate the heat released by water.
We will use the following expression.
Qw = c × m × ΔT = (4.184 J/g.°C) × 156 g × (20.5 °C - 42.9 °C)
Qw = -14.6 kJ
where,
- Qw is the heat released by water.
- c is the specific heat of water.
- m is the mass of water.
- ΔT is the change in the temperature of water.
If water releases 14.6 kJ of heat, CF₂Cl₂ absorbs 14.6 kJ of heat (Qr = 14.6 kJ).
- Step 2: Calculate the mass of the refrigerant required.
We will use the following expression.
Qr = ΔH°evap × m
m = Qr/ΔH°evap = 14.6 kJ / (0.144 kJ/g) = 101 g
where,
- Qr is the heat absorbed by the refrigerant.
- ΔH°evap is the heat of vaporization of the refrigerant.
- m is the mass of the refrigerant.
To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.
Learn more about evaporation here: brainly.com/question/25310095
