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3 years ago

What is the name of the molecule below?

Chemistry

2 answers:

ziro4ka [17]3 years ago

8 0

this is called 2-pentene. It's an alkene because it has a double bond and it's not a cyclic compound it can also be illustrated as

CH3-CH=CH-CH2-CH3

we call it 2-butene because of the position of the double bond

ehidna [41]3 years ago

4 0

Answer:

Explanation:

because of the squiggly lines

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Explain how, the removal of thermal energy (heat) from matter affects its particles.

WINSTONCH [101]

Answer:

When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises. When a substance is cooled, it loses thermal energy, which causes its particles to move more slowly and its temperature to drop.

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3 years ago

Read 2 more answers

Acetone is one of the most important solvents in organic chemistry. It is used to dissolve everything from fats and waxes to air

Yanka [14]

Answer: a. 79.6 s

b. 44.3 s

c. 191 s

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$t_{\frac{1}{2}}=\frac{0.693}{8.7\times 10^{-3}s^{-1}}=79.6s$

b) for completion of 32% of reaction

$t=\frac{2.303}{k}\log\frac{100}{100-32}$

$t=\frac{2.303}{8.7\times 10^{-3}}\log\frac{100}{68}$

$t=44.3s$

c) for completion of 81 % of reaction

$t=\frac{2.303}{k}\log\frac{100}{100-81}$

$t=\frac{2.303}{8.7\times 10^{-3}}\log\frac{100}{19}$

$t=191s$

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3 years ago

Which compound has the LEAST percent composition by mass of sulfur?

Eddi Din [679]

Answer: srs with 32.38 grams

Explanation:

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3 years ago

Why do you have to have a certain number of reactants on one side?

Debora [2.8K]

Answer:

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Explanation:

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3 years ago

The concentration of sugar in Coke is approximately 10%, or 100 ppt. If you drink

masya89 [10]

Answer:

35.5g of sugar

Explanation:

To solve this question we must assume the density of coke = Density of water = 1g/mL

Thus, in a single can of coke, the mass is 355g. Now, the 10% of this coke is sugar. That means the amount of sugar you are consuming is:

355g * (10/100) = 35.5g of sugar

7 0

3 years ago