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2 years ago

What equation represents the relationship shown in the table?

Mathematics

2 answers:

nevsk [136]2 years ago

6 0

Answer:

Step-by-step explanation:

a.) y = -x -3n-2

Keith_Richards [23]2 years ago

5 0

The answer is a
a) y = 3n - 2

You might be interested in

measure a and measure b are vertical angles with measure a = x and measure b = 4x - 30. what is measure a?

Zolol [24]

Answer:

∠a = 10°

Step-by-step explanation:

The measure of ∠a = x

The measure of ∠b = 4x-30

It is also mentioned that the measure a and measure b are vertical angles. We need to find the value of a.

For vertically opposite angles,

∠a = ∠b

x = 4x-30

4x-30=x

Taking like terms together,

4x-x= 30

3x = 30

x = 10

So, the meausre of ∠a is equal to 10°.

3 0

3 years ago

john and ted have a reputation of being late to events. If john is late 20% of the time and ted is late 40% of the time what is

oee [108]

Answer:

The probability that they will both be on time is 12/25.

Step-by-step explanation:

John is late 20% of the time.

So, he is prompt 80% of the time.

Ted is late 40% of the time.

So, he is prompt 60% of the time.

Since, both the events are independent,

p(John be on time ∩ Ted be on time) = p(John be on time) × p(Ted be on time)

$= \frac{80}{100}$ × $\frac{60}{100}$

= 0.80 × 0.60

= 0.48 or 48%

$=\frac{12}{25}$

Hence, the probability that they will both be on time is 12/25.

3 0

3 years ago

The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes

Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(completing the exam in one hour or less)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 60) =0.023= 2.3\%$

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

$P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%$

c) P(completing the exam in more than 90 minutes)

P(x > 90)

$P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

$\dfrac{15.87}{100}\times 60 = 9.52\approx 10$

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0

3 years ago

In the figure below, points J, K, and L are the midpoints of the sides of AXYZ.

Dima020 [189]

Answer:

28 ; 76 ; 38

Step-by-step explanation:

KL = $\frac{XY}{2}$ = $\frac{56}{2}$ = 28 units

YZ = 2 × JK = 38 × 2 = 76 units

LZ = 76/2 = 38 units

8 0

2 years ago

Read 2 more answers

Willie earns $7.00 per hour working. He

Alex777 [14]

Answer:

He earned $420.

Step-by-step explanation:

I hope this helps! Have a great rest of your day!

3 0

2 years ago

Read 2 more answers