Well, trees are over 20 feet tall and have trunks that are like in 2 inches and 4.5 feet about the ground. Bushes are smaller than the trees and usually have smaller, woody, bark leafs.
Well im gonna say it would be the same,but not in size.
Hope this helps
The big advantage to using continuous compounding to express growth rates is it avoids the problem of asymmetry in growth rates:
For example, if we use the normal definition and $100 grows to $105 in one time period, that's a growth rate of $105/$100 - 1 = 5% But if $105 decreases to $100, that's a growth rate of $100/$105 - 1 = -4.76%
The problem of asymmetry is those two growth rates, 5% and -4.75% are not equal up to a sign.
But if you use continuous compounding the growth rate in the first case is ln(105/100) = 0.04879.
And the growth rate in the second is ln (100/105) = -0.04879.
Those two growth rates are definitely the negative of each other.<span>
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Answer:
E(Z) > E(X)
Explanation:
X => 4.2 x 10¹¹J/50 Nucleons = 8.4 x 10⁹ J/Nu
Z => 8.4 x 10¹¹J/80 Nucleons = 1.1 x 10¹⁰ J/Nu
E(Z)1.1 x 10¹¹J/Nu > E(X)8.4 x 10⁹J/Nu
The empirical formula : C. C₁₆H₁₅N₂
<h3>Further explanation</h3>
Given
12.5 g of aniline
7.1 grams of H2O
1.48 grams of N2
Required
The empirical formula
Solution
Reaction :
mass H in H₂O :
= 2.1/18 x 7.1 g
= 0.79
mass N = 1.48
mass C :
= 12.5 g-(mass H+mass N)
= 12.5 - (0.79+1.48)
= 10.23
Mol ratio C : H : N =
= 10.23/12 : 0.79/1 : 1.48/14
= 0.853 : 0.79 : 0.106
= 8 : 7.5 : 1
= 16 : 15 : 2
Answer:
2.35 *10^2 g
Explanation:
4.2 mol Fe *55.845 g/1 mol = 234.549 > 2.35 *10^2 g
