All categories

3 years ago

If 38.5 grams of potassium react with excess oxygen gas, how many grams of potassium oxide can be produced? 4K + O2 yields 2K2O

Chemistry

1 answer:

Lera25 [3.4K]3 years ago

6 0

Answer:

46.40 g.

Explanation:

It is a stichiometric problem.

The balanced equation of the reaction: 4K + O₂ → 2K₂O.

It is clear that 4.0 moles of K reacts with 1.0 mole of oxygen produces 2.0 moles of K₂O.

We should convert the mass of K (38.5 g) into moles using the relation:

<em>n = mass / molar mass,</em>

n = (38.5 g) / (39.098 g/mol) = 0.985 mole.

<em>Using cross multiplication:</em>

4.0 moles of K produces → 2.0 moles of K₂O, from the stichiometry.

0.985 mole of K produces → ??? moles of K₂O.

∴ The number of moles of K₂O produced = (0.985 mole) (2.0 mole) / (4.0 mole) = 0.4925 mole ≅ 0.5 mole.

Now, we can get the mass of K₂O:

∴ mass = n x molar mass = (0.5 mole) (94.2 g/mol) = 46.40 g.

You might be interested in

Which element has fewer than four dots in its electron dot diagrams?

Alika [10]

Answer:

gallium (Ga)

Explanation:

the elements which have fewer than four dots in the electron dot diagrams. Explanation: Electron dot diagrams are the diagrams which represent the valence electrons in an element. The electrons are represented by the dots in these diagrams.

8 0

3 years ago

Read 2 more answers

When a teacher dilutes 50 mL of 2.0 M NaOH to 0.50 M, what volume of NaOH results?

JulijaS [17]

Answer:

= 200 mL

Explanation:

Using the dilution formula;

M1V1 = M2V2 ;

Where, M1 is the concentration before dilution, V2 is the volume before dilution, while M2 is the concentration after dilution and V2 is the volume after dilution.

M1 = 2.0 M

V1 = 50 mL

M2 = 0.50 M

V2 = ?

V2 = M1V1/M2

= ( 2.0 × 50 )/ 0.5

= 200 mL

Therefore, the volume after dilution will be, 200 mL

6 0

3 years ago

Copper was the first metal to be produced from its ore because it is the easiest to smelt, that is, to refine by heating in the

Ganezh [65]

Answer:

57.48%

Explanation:

Calculate the mass of 1 mole of malachite:

MM Cu = 63.55

MM O = 16.00

MM H = 1.01

MM C = 12.01

$(Cu_{2}(OH)_{2}CO_{3})$

A mole of malachite has:

2 moles of Cu

5 moles of O

2 moles of H

1 mole of C

MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)

MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01

MW Malachite = 221.13

Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1

Now divide the mass of Cu by the mass of Malachite

$%Cu = \frac{127.1}{221.13} =0.5748=57.48%$

7 0

4 years ago

ClO(4)− Express your answer as a chemical formula.

Nimfa-mama [501]

ClO(4)− is regarded as perchlorate ion and are produced commercially in most situations as salts via industries and in the laboratory.

<h3>What is Perchlorate ion?</h3>

This ion is referred to as a monovalent inorganic anion and is obtained by deprotonation of perchloric acid. It is composed of chlorine and oxygen atoms in the ratio 1 to 4 respectively.

This has 32 valence electrons available in the Lewis structure and is used in the commercial production of solid rocket fuel.This ion has a molar mass of 99.451 g mol−1 and is used in different processes such as an oxidizer and to control static electricity during the process of food preservation in industries.

Therefore ClO₄− is also regarded as perchlorate ion and is the most appropriate choice.

Read more about Perchlorate ion here brainly.com/question/16895150

#SPJ1

3 0

2 years ago

There are 3.45 moles of (NH4)2 SO4, how many grams is this?

blsea [12.9K]

Answer:

455.4 g

Explanation:

Data given:

no. of moles of (NH₄)₂SO₄= 3.45 mol

mass of (NH₄)₂SO₄ = ?

Solution

Formula will be used

no.of moles = mass in grams / molar mass

Rearrange the above equation for mass

mass in grams = no. of moles x molar mass . . . . . . . . (1)

molar mass of (NH₄)₂SO₄

molar mass of (NH₄)₂SO₄ = 2(14 + 4(1)) + 32 + 4(16)

molar mass of (NH₄)₂SO₄ = 2 (14 +4) + 32 + 64

molar mass of (NH₄)₂SO₄ = 2 (18) + 32 + 64

molar mass of (NH₄)₂SO₄ = 36 + 32 + 64 = 132 g/mol

Put values in equation 1

mass in grams = 3.45 mole x 132 g/mol

mass in grams = 455.4 g

So,

mass of (NH₄)₂SO₄ = 455.4 g

8 0

3 years ago