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attashe74 [19]
3 years ago
13

32.7 grams of water vapor takes up how many liters at standard temp and pressure (273 K and 100 kPa)

Chemistry
1 answer:
lana [24]3 years ago
3 0
You just need to convert the mass in grams to number of moles and use the ideal gas equation, pV = n RT

where p = 100 kPa, T = 273 K, V is the volume searched, n is the number of moles and R is the unviersal constant of gases = 8.314 J / K * mol

1) Number of moles = mass in grams / molar mass

=> n = 32.7 g / 18.0 g/mol = 1.81667 moles

2) pV = nRT => V = nRT / p

V = 1.81667 moles * 8.314 (liter*KPa /k*mol) * 273K / (100 KPa) = 41.2 liter

Answer: 41.2 liters
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Please answer ASAP!!
Alenkasestr [34]

Answer:

C.0.28 V  

Explanation:

Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

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Right answer is:

<h3>C.0.28 V </h3>

<h3 />

4 0
2 years ago
Please help!! 20 points!! Posted this previously and forgot to change it to 20 points but it is now
spayn [35]

Answer:

0.571 mol

Explanation:

Given data:

Number of moles of NaHCO₃ = 0.571 mol

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

NaHCO₃ + C₃H₆O₃   →     CO₂  + C₃H₅NaO₃ + H₂O

Now we will compare the moles of CO₂ with NaHCO₃ from balance chemical equation.

                             NaHCO₃          :            CO₂

                                    1                :               1

                                 0.571            :            0.571

So number of moles of CO₂  produced are 0.571.

3 0
3 years ago
Read 2 more answers
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