A 70 kg sailor climbs a 28.3 m rope ladder up a mast. How much work did he do?
1 answer:
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Answer:
v = 306.76 Km/h
Explanation:
given,
height of the aircraft = 3000 m
differential pressure reading = 3300 N/m²
density of air = 0.909 Kg/m³
speed of aircraft = ?
Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.
using Bernoulli's equation
where ρ is the density of the air at 3000 m
v = 85.21 m/s
v = 306.76 Km/h
Answer:
(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²
(B) Time of motion 240.2 s
Explanation:
Given;
final angular speed, ωf = 2.5 RPM
angular distance, θ = 5 rev = 5 x 2π = 10π rad
initial angular speed, ωi = 0
final angular speed in rad/s;
(A) the magnitude of its angular acceleration(rad/s^2);
(B) Time of motion;