The net current in the conductors and the value of the line integral
- The resultant remains same 3.2 *10^4 Tm
This is further explained below.
<h3>What is the net current in the conductors?</h3>
Generally,
To put it another way, the total current In flowing across a surface S (contained by C) is proportional to the line integral of the magnetic B-field (in tesla, T).
B)
In conclusion, It is possible for the line integral to go around the loop in either direction (clockwise or counterclockwise), the vector area dS to point in either of the two normal directions and Ienc, which is the net current passing through the surface S, to be positive in either direction—but both directions can be chosen as positive in this example. The right-hand rule solves these ambiguities.
The resultant remains the same at 3.2 *10^4 Tm
Read more about conductors
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Answer: C
Explanation:
when more volts are in a battery the more current you receive.
Answer:
4.3 * 10 N
Explanation:
To calculate torque, we multiply the distance from the pivot by the perpendicular (the part of the force that acts at right angles to the displacement vector) component of the force to the displacement vector from the pivot.
torque = distance from pivot * perpendicular force
170 Nm= 0.4 m * F
F = 425 N = 4.3 * 10 N rounded off to two significant figures
The formula is P = E/t, where P means power in watts, E means energy j , and t means time in seconds. This formula states that power is the consumption of energy per unit of time.
P = 15 M / 10*60
M = mega = 10⁶
15 *10⁶ / 600
= 25000 watt
The net force acting on the refrigerator is 400 N to the right.
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FURTHER EXPLANATION</h3>
The net force or resultant force is the sum of all the forces acting on a body or an object in x and y axes.
- Forces along the y-axis The forces that usually act on an object vertically (in the y-axis) are: gravitational force which is a downward force and the normal force which is an upward (perpendicular) force exerted by a surface on an object resting above it that keeps the object from falling.
- Forces along the x-axis These include the force or forces applied to cause a left or right motion of an object along the horizontal plane (called the Applied Force) and the force that opposes the motion or friction.
In this problem the forces acting on the x and y - axes can be determined:
Along the x-axis:
- gravitational force = -1960 N
- normal force = +1960 N
- Net force = -1960 N + 1960 N = 0
The gravitational force is the weight of the object obtained by multiplying the mass of the object (in kg) with the acceleration due to gravity, 9.8 m/s^2. It is given a negative (-) sign to indicate that it is a downward force.
Since the object is not falling through the surface, it can be assumed that the gravitational force and normal force are balanced. Hence, the size of the normal force is the same as the gravitational force but with the opposite direction indicated by the + sign for an upward force.
The forces along the x-axis are balanced (i.e. net force is zero) so the object neither moves upward or downward.
Along the y-axis
- applied force = +400 N
- friction = 0
- Net force = +400 N + 0 = +400 N
The applied force is +400 N. It is given a + sign to indicate that its direction is to the right.
The friction, as mentioned in the problem, is set to zero or "turned off".
The net force along the y-axis is +400. The forces are unbalanced so the object will move to the right as force is applied to it.
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Keywords: net force, resultant force
