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2 years ago

When kc decreases what happens to the molecules in terms of speed space and attractive force pls help

Chemistry

1 answer:

Fudgin [204]2 years ago

8 0

Kc decreases as the temperature in molecules increase.

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What is the mass of 1.58 moles of CH4

HACTEHA [7]

<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})$
Multiply/Divide: $\displaystyle 25.359 \ g \ CH_4$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

4 0

3 years ago

a 5-meter ramp lifts objects to a height of 0.75 meters.What is the mechanical advantage of the ramp?

coldgirl [10]

This is an Engineering question, and the answer is reasonably simple. The mechanical advantage is given by:

MA = $\frac{Distance 1}{Distance 2}$ on a lever or ramp system.

MA = $\frac{5}{0.75}$

MA = 6.67 (there are no units, as MA is a ratio)

5 0

4 years ago

calculate the amount of time required to rise the temperature of 0.50 liter of water from 0.0 c to 10.0 c if the energy is suppl

Ivanshal [37]

Answer:

The amount of time required to rise the temperature of 0.50 liter of water from 0.0 c to 10.0 c is 19 seconds

Explanation:

1100 J/s is the energy supplied so, we have to set, the energy to that ΔT, which is 10°C (10°-0°)

Q = m . C. ΔT

Q = 500g . 4,186J/g°C . 10°C

Remember the water density is 1g/mL, so if we have 0,5 L, we should get the convertion to g. (1ml = 1x10*-3 L)

1x10*-3 L ____ 1 g

0,5 L _____ (0,5 L . 1 g)/ 1x10*-3 L = 500g

4,186J/g°C, this value is known as specific heat of water. It is a known value.

Q = 500g . 4,186J/g°C . 10°C = 20930 J

Now the final rule of three:

1100 J supplies at _____ 1 second

20930 J supplies at _____ (20930 J . 1 s) / 1100 J =19,02 s

8 0

3 years ago

NEED HELPPP PLSSSSSSSSSS

Leto [7]

I would pick the first option in the third option

4 0

3 years ago

I added and multiplied i still don't know

hjlf

Answer:

it'a answer number 2

Explanation: you divide the mass by volume and 32.2 divided by 4 is 8.05

8 0

3 years ago