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Ipatiy [6.2K]
3 years ago
14

What two structures in plant leaves help prevent the loss of water?.

Chemistry
1 answer:
Gelneren [198K]3 years ago
5 0

Answer:

Upper cuticle and guard cells

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The density of H2O2 is 1.407 g/mL, and the density of O2 is 1.428 g/L. How many liters of O2 can be made from 55 mL H2O2
balandron [24]

Explanation:

mass H2O2 = 55 mL(1.407 g/mL) = 80.85 g

molar mass H2O2 = 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol

moles H2O2 = 80.85 g/34.02 g/mol = 2.377 moles H2O2

For each mole of H2O2 you obtain 0.5 mole of O2 (see the equation).

moles O2 = 2.377 moles H2O2 (1 mole O2)/(2 moles H2O2) = 1.188 moles O2

Now, you need the temperature.  If you are at STP (273 K, and 1.00 atm) then 1 mole of an ideal gas at STP has a volume of 22.4 L.  Without temperature you are not really able to continue.  I will assume you are at STP.

Volume O2 = 1.188 moles O2(22.4 L/mole) = 0.0530 L of O2.

which is  53 mL.

8 0
3 years ago
Most chemical changes in living things cannot take place without what?
lys-0071 [83]
Fire probably i dont know
5 0
3 years ago
Use the table of data for a decomposition reaction to answer the question Concentration (C) at T1 (g/L) C at T2 (g/L) C at T3 (g
Alex73 [517]

Based on the nature of chemical equilibrium, the system reached equilibrium first at the time T2.

<h3>What is chemical equilibrium?</h3>

Chemical equilibrium refers to the state of a reversible chemical reaction in which the rate of forward reaction for the the formation is equal to the rate of backward reaction for the formation of reactants.

In the table of the decomposition reaction given above, the system reached equilibrium first at the time T2 when the concentration of the reactant and products were the same.

Learn more about chemical equilibrium at: brainly.com/question/5081082

4 0
3 years ago
A 4.00L flask containing Ne at 25 C and 6.00 atm is joined by a valve to an 8.00 L flask Ar at 25 C and 2.00 atm.
timama [110]

Answer:

P=3.33atm

Explanation:

Hello!

In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:

n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr

Next, we add them up to obtain the total moles:

n_T=0.981mol+0.654mol=1.635mol

Now, the total volume:

V_T=4.00L+8.00L=12.00L

Finally, the total pressure is computed by using the ideal gas equation:

P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm

Best regards!

6 0
3 years ago
Write the bond line formula for the compound (CH3)2CHCH2C(CH3)3.​
maks197457 [2]

Formula is (CH3)2CHCH2C(CH3)3 and the name is 2,2,4-trimethylpentane

3 0
3 years ago
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