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3 years ago

I don't really understand this worksheet question.

Chemistry

1 answer:

Citrus2011 [14]3 years ago

3 0

25/2 and 96/X
CROSS MULTIPLY.

2x=2,400.
divide by 2.
x=1,200.

you take the GIVEN MASS of an element, and you put it on top, the coefficient is what it’s over. i believe this is right

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4 years ago

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3 years ago

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madreJ [45]

Answer:

$T_2= -90.0°C$

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Hello!

In this case, according to the given description of how the temperature changes for aluminum in agreement to the loss of heat of 6120.0 J, we can use the following equation:

$Q=mC\Delta T=mC(T_2-T_1)\\\\$

Thus, by knowing Q, m, C and the initial temperature, we are able to obtain:

$T_2=T_1+\frac{Q}{mC}\\\\T_2=157.3\°C+\frac{-6120.0J}{27.5g*0.900 J/g\ºC}\\\\T_2= -90.0°C$

Regards!

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3 years ago

I don't really understand this worksheet question.​

I don't really understand this worksheet question.