Answer: 0.4M
Explanation:
Given that,
Amount of moles of NaOH (n) = ?
Mass of NaOH in grams = 40.0g
For molar mass of NaOH, use the atomic masses: Na = 23g; O = 16g; H = 1g
NaOH = (23g + 16g + 1g)
= 40g/mol
Since, n = mass in grams / molar mass
n = 40.0g / 40.0g/mol
n = 1 mole
Volume of NaOH solution (v) = 2.5 L
Concentration of NaOH solution (c) = ?
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
c = 1 mole / 2.5 L
c = 0.4 mol/L (Concentration in mol/L is the same as Molarity, M)
Thus, the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution is 0.4 mol/L or 0.4M
Answer:
Element.
General Formulas and Concepts:
<u>Chemistry</u>
- Reading a Periodic Table
- Diatomic Elements
Explanation:
Diatomic Elements are elements that are bonded to themselves. Naturally, these elements are not found alone in nature.
Diatomic Elements:
Hydrogen
Nitrogen
Oxygen
Fluorine
Chlorine
Bromine
Iodine
Since Nitrogen is a diatomic element, we would find Nitrogen in nature as N₂.
Answer:
0.1357 M
Explanation:
(a) The balanced reaction is shown below as:
(b) Moles of 
can be calculated as:
Or,
Given :
For :
Molarity = 0.1450 M
Volume = 10.00 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 10×10⁻³ L
Thus, moles of :
Moles of = 0.00145 moles
From the reaction,
1 mole of react with 2 moles of NaOH
0.00145 mole of react with 2*0.00145 mole of NaOH
Moles of NaOH = 0.0029 moles
Volume = 21.37 mL = 21.37×10⁻³ L
Molarity = Moles / Volume = 0.0029 / 21.37×10⁻³ M = 0.1357 M
Answer:
im scared of high school now after i saw this.
Explanation:
I don't want to learn that
Answer : The number of moles of 
are 0.50 moles.
Solution : Given,
Volume solution = 0.25 L
Molarity of solution = 2.00 mole/L
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
Now put all the given values in this formula, we get number of moles.
By rearranging the term,
Number of moles of = 0.50 moles
Therefore, 0.50 moles of are there in the solution.
