Explanation:
conservation of mass that states that matter cannot be created or destroyed,it is consvered.
Answer:
<u>The effective nucleus charge increases on going from left to right.</u>
<u></u>
Explanation:
There are two factors that determine the atomic size of the atom.
1. Shielding constant :It is the shielding of the outershell electron from the nucleus by the inner shell electron. Thses are repulsive forces.If the value of shielding contant is more , then the size of the element increases.
2.The Effective Nuclear Charge : The net attraction of the nucleus felt by the electron present in the outermost shell . It is represented by Zeff.
This is attractive force.
If the Zeff is more then the nucleus of the element will pull the electron cloud more strongly.This leads to decrease in the size of the element.
On going left to right ,each time one electron is added to the element .This electron attracts the nucleus more strongly<u><em>(the nucleus is Positive charge and the electron is negative charge, opposite charge attracts each other</em></u>). Hence , the size decreases.
Thus, in period two , there is decrease in the atomic radius with increasing atomic number because the effective nuclear charge increases on going from left to right.
Answer:
STP conditions, which are defined as a pressure of 100 kPa and a temperature of 273.15 K, should immediately get you thinking about molar volume of a gas.
More specifically, about the fact that 1 mole of any ideal gas occupies exactly 22.7 L at STP.
This means that all you really need to figure out is the number of moles of oxygen that took part in the reaction. If you know how many moles of oxygen are needed, you can use the molar volume of a gas at STP to calculate the volume of oxygen.
Use water's molar mass to determine how many moles of water would the reaction produce
Answer:
They have electrons in their 3d- and 4s-orbital for bond formation.
Explanation:
d- metals or transition metal are metal which form ion with partially filled d-orbital. Examples are iron and manganese.
The metals have 2 electrons in their 4s orbital. If only this is used for bonding, they will form compounds where they have oxidation State of +2 as seen in MnO.
If two 4s and one of 3d electrons are used, oxidation state of +3 is formed as seen in FeCl3.
If two 2s electron I used with two 3d electrons, compound with oxidation state of +4 is formed as seen in MnO2