Question

How many moles of Ba(NO3)2 are there in 0.25 L of a 2.00 M Ba(NO3)2 solution?

Answer 1

Answer:

the answer is 0.50 mol

Explanation:

because that's the answer

Answer 2

Answer : The number of moles of $Ba(NO_3)_2$ are 0.50 moles.

Solution : Given,

Volume solution = 0.25 L

Molarity of solution = 2.00 mole/L

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{\text{ Number of moles of solute}}{\text{ Volume of solution}}$

Now put all the given values in this formula, we get number of moles.

$2.00mole/L=\frac{\text{ number of moles of }Ba(NO_3)_2}{0.25L}$

By rearranging the term,

Number of moles of $Ba(NO_3)_2$ = 0.50 moles

Therefore, 0.50 moles of $Ba(NO_3)_2$ are there in the solution.